A ball is thrown upward, with an initial velocity of 44 meters per second, at an angle of 68° with respect to the horizontal. The ball is thrown from a helght of 3 meters off the ground. The horizontal distance x from the starting point and the height y above the ground of the ball t seconds after it is thrown are given by the parametric equations below. x-(", cos e)t y=-4.9+(vo sin e)r +h Here vo is the initial velocity, 0 is the initial angle with respect to the horizontal, and h is the initial height. Use the equations to answer the following questions. (a) When does the ball reach its maximum height? Do not round any intermediate computations. Round your answer to the nearest hundredth. O seconds (b) What is the maximum height of the ball? Round your answer to the nearest tenth. I meters

A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as functions of time are given by  x = 17.0t  and  y = 4.20t − 4.90t2,  where x and y are in meters and t is in seconds. (a) Write a vector expression for the ball's position as a function of time, using the unit vectors î and ĵ. (Give the answer in terms of t.) =          m By taking derivatives, do the following. (Give the answers in terms of t.) (b) obtain the expression for the velocity vector  as a function of time =          m/s(c) obtain the expression for the acceleration vector  as a function of time =          m/s2(d) Next use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the golf ball at t = 3.24 s.   =         m   =         m/s   =         m/s2

An object has an initial velocity of 29.0 m/s at 95.0° and an acceleration of 1.90 m/s2 at 200.0°. Assume that all angles are measured with respect to the positive x-axis. (a) Write the initial velocity vector and the acceleration vector in unit vector notation. (b) If the object maintains this acceleration for 12.0 seconds, determine the average velocity vector over the time interval. Express your answer in your unit vector notation.

A golf ball is hit upward, with an initial velocity of 47 meters per second, at an angle of 25° with respect to the horizontal. The ball is hit from a height of 8 meters above the ground.   The horizontal distance x from the starting point and the height y above the ground of the ball t seconds after it is hit are given by the parametric equations below.   x=(v0cosθ)t y=−4.9t^2+(v0sinθ)t+h Here v0 is the initial velocity, θ is the initial angle with respect to the horizontal, and h is the initial height.   Use the equations to answer the following questions.   (a)How long is the ball in the air before it first touches the ground?Do not round any intermediate computations. Round your answer to the nearest hundredth. _____ seconds (b)What is the horizontal distance the ball travels before it first touches the ground?Round your answer to the nearest whole number. _____ meters