College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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(a) A device consists of an object with a weight of 40.0 N hanging vertically from a spring with a spring constant of 250 N/m. There is negligible damping of the oscillating system. Applied to the system is a harmonic driving force of 11.0 Hz, which causes the object to oscillate with an amplitude of 4.00 cm. What is the maximum value of the driving force (in N)? (Enter the magnitude.) 769.11 N ✓ (b) What If? The device is altered so that there is a damping coefficient of b = 5.00 N s/m. The hanging weight and spring constant remain the same. The same driving force as found in part (a) is applied with the same frequency. What is the new amplitude (in cm) of oscillation? 6.523 cm. x Enter a number. (c) What If? Repeat the same calculation as part (b), only now with damping coefficient of b = 100 N s/m. (Enter the answer in cm.) Show transcribed image text Answers narendra answered this 1,701 answers Solution: Given That m= 40 g 201 - من 2 = 2πT XII = 69.11 rad|s x= no Sin wt No = 4cm amplitude Xo Here 501 что =4.08 ку 9.8 = 0.04 m folk √(1-9) 7(269) ² 7 Fo= q f 6= 69-11 حبا соп O con = Was this answer helpful? 250×9.8 m 40 wn = 7.8262 radls q= 69.11 = 8.83 7.8261 Xo (9²-1) k Fo=769.689 N k=250N/m m TS = 0.04 (8.83²-1) (250) 5 F = Fosin t 0 View Ⓒ C= 5N-1/m Xo = Xo f = f Xo = f= = f: Xo = 0.0399 Хо Xo = √(1-9²1²+(279)² 5 Xo = 4cm Xo = Zoom 2X408x7.8262 0.07829 769.689/250 √(1-(8.833²)² + (2x0.07829x8.83) ² 769.689/250 76.9813 3.99 = 4 Cm Share Highlight 100 2x4.08 x 7.8262 1.5658 (cc = 2mwn) 769,689/250 (1-8.83²)² + (2x1.5658X8,833² 769689/250 81.7853 Xo = 3.764 cm = 0.03764
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Transcribed Image Text:(a) A device consists of an object with a weight of 40.0 N hanging vertically from a spring with a spring constant of 250 N/m. There is negligible damping of the oscillating system. Applied to the system is a harmonic driving force of 11.0 Hz, which causes the object to oscillate with an amplitude of 4.00 cm. What is the maximum value of the driving force (in N)? (Enter the magnitude.) 769.11 N ✓ (b) What If? The device is altered so that there is a damping coefficient of b = 5.00 N s/m. The hanging weight and spring constant remain the same. The same driving force as found in part (a) is applied with the same frequency. What is the new amplitude (in cm) of oscillation? 6.523 cm. x Enter a number. (c) What If? Repeat the same calculation as part (b), only now with damping coefficient of b = 100 N s/m. (Enter the answer in cm.) Show transcribed image text Answers narendra answered this 1,701 answers Solution: Given That m= 40 g 201 - من 2 = 2πT XII = 69.11 rad|s x= no Sin wt No = 4cm amplitude Xo Here 501 что =4.08 ку 9.8 = 0.04 m folk √(1-9) 7(269) ² 7 Fo= q f 6= 69-11 حبا соп O con = Was this answer helpful? 250×9.8 m 40 wn = 7.8262 radls q= 69.11 = 8.83 7.8261 Xo (9²-1) k Fo=769.689 N k=250N/m m TS = 0.04 (8.83²-1) (250) 5 F = Fosin t 0 View Ⓒ C= 5N-1/m Xo = Xo f = f Xo = f= = f: Xo = 0.0399 Хо Xo = √(1-9²1²+(279)² 5 Xo = 4cm Xo = Zoom 2X408x7.8262 0.07829 769.689/250 √(1-(8.833²)² + (2x0.07829x8.83) ² 769.689/250 76.9813 3.99 = 4 Cm Share Highlight 100 2x4.08 x 7.8262 1.5658 (cc = 2mwn) 769,689/250 (1-8.83²)² + (2x1.5658X8,833² 769689/250 81.7853 Xo = 3.764 cm = 0.03764
(a) A device consists of an object with a weight of 25.0 N hanging vertically from a spring with a spring constant of 250 N/m. There is negligible damping of the oscillating system. Applied to the system is a harmonic driving force of 13.0 Hz, which causes the object to oscillate with an amplitude of 4.00 cm. What is the maximum value of the driving force (in N)? (Enter the magnitude.) 670.8 N (b) What If? The device is altered so that there is a damping coefficient of b = 5.00 N. s/m. The hanging weight and spring constant remain the same. The same driving force as found in part (a) is applied with the same frequency. What is the new amplitude (in cm) of oscillation? cm (c) What If? Repeat the same calculation as part (b), only now with a damping coefficient of b = 100 N s/m. (Enter the answer in cm.) cm
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Transcribed Image Text:(a) A device consists of an object with a weight of 25.0 N hanging vertically from a spring with a spring constant of 250 N/m. There is negligible damping of the oscillating system. Applied to the system is a harmonic driving force of 13.0 Hz, which causes the object to oscillate with an amplitude of 4.00 cm. What is the maximum value of the driving force (in N)? (Enter the magnitude.) 670.8 N (b) What If? The device is altered so that there is a damping coefficient of b = 5.00 N. s/m. The hanging weight and spring constant remain the same. The same driving force as found in part (a) is applied with the same frequency. What is the new amplitude (in cm) of oscillation? cm (c) What If? Repeat the same calculation as part (b), only now with a damping coefficient of b = 100 N s/m. (Enter the answer in cm.) cm
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