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5.1
a) A 2.00 kg block with initial speed 1.50 m/s slides across a horizontal surface for 0.750 m
before coming to rest. Assuming that the frictional force between the block and table is
constant over that time, calculate its magnitude.
b) Jump vertically as high as you can from the ground. Use conservation of energy to
estimate your speed just as you leave the ground. (A range of values is acceptable here,
depending on your estimate of how much you can change your center of mass location!)
c) You are trying to design a “rail gun" on the Moon (of mass MM = 7.36x1022 kg and
radius RM = 1740 km) to launch canisters with mass m at a high speed vi, on an initially
nearly horizontal track along the Moon's surface. If vi is large enough, the canisters will
fly tangentially away from the moon into deep space. You want the canisters to have a
certain speed, vf, when they are very far from the Moon.
i) Find an expression for vi in terms of RM, MM, G, and vf.
ii) Say you want vf = 500 m/s. Calculate a numerical value for launch speed, vi.
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Transcribed Image Text:5.1 a) A 2.00 kg block with initial speed 1.50 m/s slides across a horizontal surface for 0.750 m before coming to rest. Assuming that the frictional force between the block and table is constant over that time, calculate its magnitude. b) Jump vertically as high as you can from the ground. Use conservation of energy to estimate your speed just as you leave the ground. (A range of values is acceptable here, depending on your estimate of how much you can change your center of mass location!) c) You are trying to design a “rail gun" on the Moon (of mass MM = 7.36x1022 kg and radius RM = 1740 km) to launch canisters with mass m at a high speed vi, on an initially nearly horizontal track along the Moon's surface. If vi is large enough, the canisters will fly tangentially away from the moon into deep space. You want the canisters to have a certain speed, vf, when they are very far from the Moon. i) Find an expression for vi in terms of RM, MM, G, and vf. ii) Say you want vf = 500 m/s. Calculate a numerical value for launch speed, vi.
Expert Solution
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Step 1

The 2 kg block is moving with an initial speed of 1.5 m/s across a horizontal surface.

Owing to this initial velocity, the initial kinetic energy of the block is

K=12mv2m is the mass and v is the velocity of the blockm=2 kgv=1.5 m/sK=12×2×1.52K=2.25 J

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