**Problem Description:**The 1.0 kg block in Figure 1 is tied to the wall with a rope. It sits on top of the 2.0 kg block. The lower block is pulled to the right with a tension force of 20 N. The coefficient of kinetic friction at both the lower and upper surfaces of the 2.0 kg block is \( \mu_k = 0.39 \).For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution on the topic of a Car on a rolling board.**Questions:**1. **Tension in the Rope:** - What is the tension in the rope holding the 1.0 kg block to the wall? - **Express your answer with the appropriate units:** - **Answer:** 3.8 N - **Outcome:** Correct - **Feedback:** Here we learn how to calculate the kinetic friction force.2. **Acceleration of the 2.0 kg Block:** - What is the acceleration of the 2.0 kg block? - **Express your answer with the appropriate units:** - **Outcome:** Incorrect; Try Again**Figure Description:**- The diagram shows two blocks stacked vertically. - The top block is labeled as 1.0 kg. - The bottom block is labeled as 2.0 kg.- A rope connects the top block to the wall.- A horizontal force of 20 N is applied to the right on the bottom block.This setup is used to explore concepts related to tension, friction, and acceleration in physics.

Name: **Problem Description:**The 1.0 kg block in Figure 1 is tied to the w
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: **Problem Description:**The 1.0 kg block in Figure 1 is tied to the wall with a rope. It sits on top of the 2.0 kg block. The lower block is pulled to the right with a tension force of 20 N. The coefficient of kinetic friction at both the lower and

Given-Coefficient of kinetic friction is mass of the upper block is m1=1 kgmass of the lower block is m2 = 2 kg(a)The tension of the rope holding the 1kg block is equal to the the force of friction on the top of the 2kg block.Part (a)Part (b)