(a) A 1.00 cm-high object is placed 4.10 cm to the left of a converging lens of focal length 8.35 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. Is the image inverted or upright? Is the image real or virtual? (b) What If? If an image of opposite characteristic, i.e., virtual if the image in part (a) is real and real if the image in part (a) is virtual, is to be obtained, what is the minimum distance (in cm), and in which direction, that the object must be moved from its original position?

icon
Related questions
Question
(a) A 1.00 cm-high object is placed 4.10 cm to the left of a converging lens of focal length 8.35 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image.
Is the image inverted or upright?
Is the image real or virtual?
(b) What If? If an image of opposite characteristic, i.e., virtual if the image in part (a) is real and real if the image in part (a) is virtual, is to be obtained, what is the minimum distance (in cm), and in which direction, that the object must be moved from its
original position?
Transcribed Image Text:(a) A 1.00 cm-high object is placed 4.10 cm to the left of a converging lens of focal length 8.35 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. Is the image inverted or upright? Is the image real or virtual? (b) What If? If an image of opposite characteristic, i.e., virtual if the image in part (a) is real and real if the image in part (a) is virtual, is to be obtained, what is the minimum distance (in cm), and in which direction, that the object must be moved from its original position?
Expert Solution
steps

Step by step

Solved in 2 steps with 4 images

Blurred answer