A 95% confidence interval for the average annual employee turnover rate ofAustralian businesses was found to be (47% to 63%). Which of the following is acorrect interpretation of this interval?A. 95% of businesses have at least at 47% annual employee turnover rateB. We can be 95% confident that the population mean employee turnoverrate is between 47% and 63%C. 63% of businesses have at least a 47% annual employee turnover rateD. We can be 47% confident that the population employee turnover rate isbetween 63% and 95%E. We can be 95% confident that the population proportion of businessesthat make a profit is between 47% and 63%

95% ci for average annual employee turnover rate is : (47% to 63%) we have to interprete this ci.

Answered: A 95% confidence interval for the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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When a population has less variability, for the same margin of error and confidence level, the confidence interval becomes a. larger b. smaller c. of unchanged size
If [0.64, 0.82] is a confidence interval for the population proportion. Find the value of the point estimator of the population proportion. Select one: O a. 0.73 O b. 0.70 O c. 0.74 O d. 0.72
Please explain step by step
If [1740, 1850 is a confidence interval for a population mean. Find the margin of error. Select one: a. 60 O b. 80 C. 55 O d. 40
Report an appropriate hypothesis test for a positive linear relationship and use a 5% significance level. Explain the potential error in words, in context. In the answer options below I have used the phrase “a certain relationship” because I don’t want to give away exactly what type of relationship it is. Group of answer choices We would be accepting that there was a certain relationship between Sale amount and Tip when actually there wasn’t. We would not be accepting that there was a certain relationship between Sale amount and Tip when indeed there wasn’t. We would not be accepting that there was a certain relationship between Sale amount and Tip when actually there was. We would be accepting that there was a certain relationship between Sale amount and Tip when indeed there was.
Thelma and Louise are each attempting to estimate the proportion of adults who enjoy listening to country music. They each survey a different random sample of adults, and in each sample, the proportion who say they enjoy listening to country music is 0.29. Thelma and Louise each use their sample data to construct a confidence interval. Thelma's interval is from 0.242 to 0.338 and Louise's interval is from 0.237 to 0.323. One of these intervals was computed correctly and the other was not. Which interval must be the correct one? It's impossible to answer this question without knowing the level of confidence used for each interval. It's impossible to answer this question without knowing the sample sizes. O It's impossible to answer this question without knowing the sample sizes or the level of confidence used for each interval. Thelma's interval must be the correct interval. O Louise's interval must be the correct interval.
15. Pain after surgery: In a random sample of 50 patients undergoing a standard surgical procedure, 15 required medication for postoperative pain. In a random sample of 90 patients undergoing a new procedure, only 16 required pain medication. a. Construct a 95% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. b. A physician claims that the proportion of patients who need pain medication is the same for both procedures. Does the confidence interval contradict this claim? 16
option d. for the last question is D. The P-value is greater than the level of significance so there is not sufficient evidence to conclude the new system is effective.
8. A confidence interval for estimating the mean An industrial/organizational psychologist wants to improve worker productivity for a client firm, but first he needs to gain a better understanding of the life of the typical white-collar professional. Fortunately, he has access to the 2008 Workplace Productivity Survey, commissioned by LexisNexis and prepared by WorldOne Research, which surveyed a sample of 650 white-collar professionals (250 legal professionals and 400 other professionals). One of the survey questions was, “How many work-related emails do you receive during a typical workday?” For the subsample of legal professionals (n = 250), the mean response was M = 36.7 emails, with a sample standard deviation of s = 23.8 emails. The estimated standard error is sMM? = A-0.085, B-1.341, C-0.095 or D-1.505 (choices to choose from.) . Use the following Distributions tool to develop a 90% confidence interval estimate of the mean number of work-related emails legal…
You want to create a confidence interval for the difference in the percent of people over 40 who took music lessons as children and the percent of people 20-40 who took music lessons as children. You decide to use the Plus Four method. You ask 30 people over 40 and find that 21 of them took music lessons as children. You ask 25 people 20-40 and find that 13 took music lessons as children. Fill in the blanks for what you would put into your calculator's interval function. Have people over 40 be group 1. X1 = n1 = X2 = n2 =
9. According to a poll, eighty seven percent (87%) of California adults (440 out of 506 surveyed) feel that education is one of the top issues facing California. We wish to construct a ninety percent (90%) confidence interval for the true proportion of California adults who feel that education is one of the top issues facing California.What is a point estimate for the true population proportion?
8.2 Question 3). According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, Arkansas had 1,601 complaints of identity theft out of 3,482 consumer complaints ("Consumer fraud and," 2008). Calculate a 90% confidence interval for the proportion of identity theft in Arkansas.

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