A 9 cm diameter solid aluminum post is subjected to a horizontal force of V= 8.1 kN and a concentrated torque of T = 7.8 kNm, acting in the directions shown in the figure below. Assume that L = 0.5 m. The yield strength of the aluminum is oy = 250 MPa. Determine at point K: a) Normal stress due to bending caused by V. Enter your answer in MPa to 2 decimal places.

The state of plane stress at a point is represented by the element shown in the figure. Oy o, = 200 Mpa oy = 450 Mpa Txy Try 3D200 Мра Click here to see all formulas Ox Part A - Determine the maximum principal stress in Mpa. O 253 О 355 O 507 O 760 O 608 Submit Request Answer O O O O O

1- The shaft shown in the below Fig. consists of a 75-mm diameter aluminum segment rigidly joined to a 50-mm diameter steel segment. The ends of the shaft are attached to rigid supports. Calculate the maximum shear stress developed in each segment when the torque T = 1130 N.m. is applied. Use G = 28 GPa for aluminum and G = 83 GPa for steel. %3D %3D Aluminum Steel 75 mm diameter 50 mm diameter 1130 N.m Tal 1st 2 m 1 m

A steel shaft with a length of 3.00 m. One meter of the steel is contained in a brass tube and firmly attached. The diameter d1 = 70 mm and the diameter d2 = 90 mm. Brass G = 39GPa and steel G = 77.20 GPa. Determine: The torque that can be applied if the deformation at one end is 10 degrees. Answer: T = 8.64 kN – m The torque that can be applied if the maximum shear stress in brass is 70MPa and in steel is 110MPa. Answer: T = 6.352 kN – m Recommendation: analyze by segments. The first segment is only brass, then the composite part between brass and steel, and the last part only steel. In the composite segment, use only one material. In this same segment, equalize the deformations.

3) Solve the plane stress problem using two-element model to find displacements and stresses. 15 kN 30 mm E-70 GPa Thickness - 10 mm

Given the stress element shown, determine the maximum in-plane shear stress, 0x = 54 MPa Oy = 30 MPa Txy = 40 MPa (Use the stress orientation shown in the figure to determine the sign on the stress values.) 58 MPal 65 MPa 74 MPa 88 MPa 96 MPa + 148 MPa

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A shaft is subjected to a torque of 28 kNm and a maximum bending moment of 25 kNm. The shaft is solid with a diameter of 125 mm. Using the Mohr circle method find the values for the principal stresses and themaximum shear stresses on the shaft i)Construct the Mohr circle on the graph paper provided. ii) Using the Mohr circle method find the values for the principal stresses and the maximum shear stresses on the shaft.iii) Show the orientations of the planes on which the principal stresses act on a rotatedelement

A pipe has an outside diameter of 0.7 inches and inside diameter of 0.12 inches. A force of 411 lbs is applied at the end of a 1.7 in lever arm, causing the pipe to twist. What is the maximum stress in the pipe in psi? 20,766.9 Correct Answer: 124,601

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