A 72%| 4:42 PM Wed Feb 12 88 chem 1b readings chem 1b readings chem 1B discussion T| μ L 11Z(5) 20 17.55 25 23.78 30 31.86 (D) 0.0144 g (E) 0.0449 g (A) 0.0196 g (B) 0.0717 g (C) 0.0190 g J(13) The mole fraction of carbon dioxide in dry air near sea level is 0.000375, where the molar mass of carbon dioxide is 44.010. The partial pressure of carbon dioxide when the total atmospheric pressure (dry air) is 97.5 kPa is kPa. (C) 0.0370 (E) 8.40 × 10-4 (A) 2.63 × 105 (В) 5.97 х 103 (D) 1.63 (14) The concentration of carbon monoxide in a sample of air is 9.2 ppm. There are molecules of CO in 1.00 L of this air at 755 torr and 23°C. (A) 3.8 × 10-7 (B) 2.2 × 1021 (C) 2.9 × 1018 (D) 1.7 × 1020 (E) 2.3 × 1017

0.90 3.17 1.35 7.3 ppm 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 Ppm ******** <-7.385 -7.363 7.262 0.90 0.95 -2.160 1.00 -1.556 1.35 1.419 .401 1.384 1.63 5.21 Pp 7.0 6.8 ppm 1.00 4.0 ppm 7.385 7.363 7.262 7.083 7.066 7.019 6.965 6.893 6.862 -6.840 -6.893 -6.862 --6.840 4.035 4.018 4.000 3.983 4.035 4.018 4.000 3.983 -2.160 1.556 1.419 1.401 -1.384 ---0.000 NMR tube. Assign all peaks that have been integrated. Below is a real spectrum of the molecule below, shown taken in CDCl3, in a recently cleaned

Using the Solubility Data for Report below answer the question: Compound                      Cold water Solubility               Hot Water Solubility Benzoic Acid            0.42 g per 100mL of water    5.79 g per 100mL of water Impurity                    0.61 g per 100mL of water     4.62 g per 100mL of water An impure sample contains 1.14 g of impurities and 5.14 g of benzoic acid. The sample is dissloved in 100mL of water and heated. The solution is then cooled. How many grams of impurity will crystalize when the solution has cooled?

I need to make a 500ml solution with 7.49 ug/ml linoleic acid and I have 1.07 g/ml linoleic acid to use. How much linoleic acid do I need to make my 500ml solution at said concentration?