A 70 μF capacitor with a 13 μC charge is connected across a 18 mH inductor. What is the charge on the capacitor and what is the current through the inductor 0.55 ms after the circuit is connected?

Q104 You have the following circuit: When a charged capacitor is linked to an inductor, it induces a current to pass through the inductor, depleting the capacitor's charge until it is entirely discharged. The current flowing in the inductor, in return, charges up the capacitor until it becomes fully charged. If Q(t) denotes the charge on the capacitor at time t, and I represents the current, then. dQ I= L-10-9-0 dt² dt In the case that the resistance in the circuit is zero, Charge Q and current I would satisfy the differential equation shown below: 2-0 d²Q Ldt² L=dI dt In which L denotes the inductance and C denotes the capacitance, so the following equation can be made; 2=0 inductor Q(t)=_ HH capacitor In the same way that a spring can experience a damping force influencing its movement, a circuit can also have a similar effect introduced by the resistor. The resistor, with a resistance denoted by R, plays a role in this process. dQ *Rd 2 + &Q=0 m b) Q(0)=2 & Q'(0)=0 Q(t)= resistor…

The voltage across an inductor is proportional to the inductor and the derivative of the current that flow through it.   Is it True or False?

charge and the current (i) is zero, then P= 0. If q =0 at time t =0, then =±n/2. Example: A 300-V dc power supply is used to charge a 25-µF capacitor. After the capacitor is fully charged, it is disconnected from the power supply and connected across a 10-mH inductor. The resistance in the circuit is negligible. (a) Find the frequency and period of oscillation of the circuit. (b) Find the capacitor charge and the circuit current 1.2 ms after the inductor and capacitor are connected. Then find for the magnetic and electric energies (c) at and (d) at t = 1.2 ms. Given: C = 25 x 106 F L = 10 x 103 H t = 1.2 x 103 s (c) Solving for magnetic (UB) and electric (UE) energies at time t =0. Solution: (7.5 x 10-3 C)? (a) Solving for angular frequency (w)and period (T) Ug =Li? = 0 Ug = 2C - 1.1 J 2(25 x 10-6 F) 1 = 2.03 x 10° rad/s (10 x 10-3H)(25 x 10¬°F) (d) Solving for magnetic (UB) and electric (UE) energies at time t =1.2 ms. 2. 03 х 103 Рad Ug = }Li² = }(10 × 10-3 H)(-10 A)² = 0.5 J f = 320…

The current in the RL circuit shown below reaches half its maximum value in 0.5 ms after the switch S1 is thrown. Determine (a) the time constant of the circuit and (b) the resistance of the circuit if L = 200 mH. R Hints a. The time constant is TL = ms. b. The resistance R is Ω.

The current flowing through a circuit is changing at a rate of 6.00 A/s. If the circuit contains a 190.0 H inductor, what is the emf across the inductor?

An inductor L = 0.025 H and a 40 Ω resistor are connected in series to a 5 volt battery and a switch. At t = 0, the switch is closed to complete the circuit. a) What is the potential difference across the resistor a long time after the switch is closed? b) From the time the switch is closed, how long does it take for the current to reach 63% of the maximum value? c) For a single loop circuit with a 2 Ω resistor, a single battery of 3 V, and a characteristic size (size of the loop) of 15.0 cm, the estimated inductance is 2 ✕ 10−7 H. What is the time constant of this RL circuit?

A7.00 µF capacitor is connected to a 12.5 mH inductor as shown in the circuit above. What happens to the current when the switch is closed? No currrent flows in the circuit. O The current will begin to oscillate in the circuit. O The current flows and is disspated in the inductor.

For an RLC circuit in the limit of very high frequency, what is the effective behavior of the capacitor and the inductor in the circuit? O A. The inductor acts like a very large resistance and the capacitor acts like a very small resistance. O B. The inductor acts like a very small resistance and the capacitor acts like a very small resistance. OC. The inductor acts like a very large resistance and the capacitor acts like a very large resistance. O D. The inductor acts like a very small resistance and the capacitor acts like a very large resistance. 9:44 PM A

A 2.2 Henry inductor and a 177Ω resistor are connected in series with a 24V battery.  A long time later the battery is removed from the circuit and replaced with a conducting wire so the inductor is in series with the resistor. After 10.716 ms have gone by what is the magnitude of the current through the resistor in mA?