A 7-degree curve branches off a 3 degrees main curve in an opposite direction in the layout of a B.G. yard. If the speed on the branch line is restricted to (25+Z) kmph, determine the speed restriction on the mainline. Assume permissible deficiency in can't as 76 mm. [Here, Z = last three digit of student ID x 0.05 (if student ID
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- If the curve lead of a BG turnout is 16.76m, the angle of crossing of the turnout will be given by -1 A tan 5 B D LO 1 tan 5 C) tan 5 tan ¹10 1 -1 tan 10From a BG main line curve of 2º, a 1: 12 turnout takes off in contrary flexure for a branch line. The speed on the branch line is restricted to 42 km/hr. Determine the speed restriction on the main line. Assume permissible deficiency in cant as 75 mm.A branch track of 6° diverts from main track of 3° in an opposite direction in a layout of BG track. Calculate the maximum speed permissible for branch track, if on the main track, maximum speed permitted is 60 kmph.
- A H.C questions .pco | C/Users/anwar/Downloads/Telegram%20Desktop/H.C%20questions%20 %20.pdf Maps ID Page view A Read aloud Highlight Erase Q6. Given horizontal curve has two-lanes with lower-than-average coefficient of side friction (0.1) and no superelevation. The lane width is 4-meter. The curve has a radius of 500 meter and a design speed of 80 km/hr check the safety of this curve. How can you show this?8. For a BG main line curve of 2°, a 1 in 12 turnout takes off in similar flexure for a loop. The turnout is immediately followed by a reverse curve. Find out the permissible cant on the main line and the speed that can be permitted. Take speed on turnout track as 15 kmph and permissible deficiency in cant as 75 mm.An 8° curve track diverges from a main curve of 5° in the opposite direction. In the layout of a BG yard, calculate the superelevation and the speed on the branch line when the maximum speed permitted on the main line is 45km/h.
- Traffic Engineering vertical curve problem. Solve the d,e,f partCalculate the super elevation and maximum permissible speed for a 3° Meter Gauge transitioned curve on a high-speed route. The speed for calculating the equilibrium super elevation as decided by the chief engineer is 80 km/h, maximum sanctioned speed of 110 km/h and the goods train's speed is to be 50km/h. Permissible S.E deficiency is 75mm.Calculate the maximum permissible speed on curve of high speed B.G. track having the following particulars: Degree of the curve =2°, Amount of superelevation = 150 m, Max. speed of the section likely to be sanctioned = 165 kmph. = 8.0 cm, Length of transition curve
- Q-A cross-over occur between two Meter Gauge parallel tracks of same crossing number 1 in 12 with straight intermediate portion between the reverse curves and the distance between the centers of tracks is 3.5 m. If the value of G is 1 m, find the intermediate straight distance.A grade of vertical curve can expressed as be O O O O O O A-In terms of percent O D-Both A and B C-In terms of number B-In terms of ratio O E-None of above. D Q1/A horizontal curve with degree of curvature of 4° and intersection angle of 55°25", the PC is located at station 238 +44.75. Determine the deflection angles and the chord lengths for setting out the curve at whole stations from the P.C? Q2/ For mass. Hand diagram with following data: . Cost of overhaul: 1500 ID/m3.station. ex Cost of free haul: 5000 ID/m3 Cost of borrow 6000 ID/m3 Free haul distance (F.H.D) = 700m, . Cost of waste-free haul dist.-4500 ID/m3 Find cost for length of earth = 500m if you know L.E.H-11 Sta. 700 m