A 68 g sample of a compound used as a dry cleaning fluid is found to contain 10.80 g carbon, 1.36 g hydrogen and 47.84 g chlorine.  What is the subscript of hydrogen in the empirical formula for the compound?

Q: A 58.5 g sample of an unknown compound that contains only carbon, hydrogen and oxygen was analyzed…

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Q: rgahic compound has a gram molecular weight of 372 g/mol, and its composition is 38.6% carbon, 9.76%…

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Q: A compound contains only carbon, hydrogen, nitrogen, and sulphur. A combustion analyzer collects…

A: Given, A compound contains only carbon hydrogen, nitrogen and sulpur. The combustion analyzer…

Q: What is the molecular formula of an unknown compound which is composed of 57.14% carbon, 27.18 %…

A: Molecular formula = (Empirical formula)n where n = No of empirical formula components that combine…

Q: Be sure to answer all parts. How many total moles of ions are released when the following sample…

A: To solve this problem we have to calculate the number of moles.

Q: When 1.615 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 5.545 grams…

A: The molecular formula is a formula generated from molecules that represents the total number of…

Q: molecular formula

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Q: An organic compound consists of Carbon, hydrogen and sulfur. Complete combustion of 3.50 g this…

A: The given compound consist of carbon, hydrogen and sulfur. We have to determine the empirical…

Q: An unknown compound is processed using elemental analysis and found to contain 117.4 g of platinum,…

A: We know that,  Number of mole = given mass/molar mass Atomic mass of platinum =195.084 g

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 4.83 g H2O. What is the empirical…

A: Given : Mass of CO2 produced = 33.01 g Mass of H2O produced = 4.83 g And the compound is…

Q: A sample of urea contains 1.233 g N, 0.177 g H, 0.528 g C, and 0.704 g O. What is the empirical…

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Q: An ionic compound was formed by combining 8.289 g of copper (Cu) with 1.218 g of nitrogen (N). What…

A: Given that, Mass of copper Cu = 8.289 g Moles of Cu in 8.289 g = 8.289 g/63.546 g/mol = 0.13044 mol…

Q: In 1871, Mendeleev predicted the undiscovered element ekasilicon. In 1886, the element was…

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Q: A 50.00 g sample of an organic compound containing only C, H and O is analyzed by combustion…

A: The objective of the question is to determine the empirical formula of the organic compound…

Q: A compound contains only C, H, and N. Combustion of 35.0 mg of the compound produces 54.9 mg CO2 and…

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Q: What is the empirical formula for a compound when nitrogen is 1.121 g, hydrogen 0.161 g, carbon is…

A: Empirical formula :-  The chemical formula which shows only the relative number (simplest ratio) of…

Q: When 3.433 grams of a hydrocarbon, C,Hy, were burnec in a combustion analysis apparatus, 10.52 grams…

A: Mass of Hydrocarbon = 3.433 grams Molar mass of Hydrocarbon = 86.18 grams Number of moles of…

Q: A compound contains carbon, hydrogen, and sulphur. A combustion analyzer collects 45.0 g of CO2,…

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Q: A 2.86 g sample of a compound consisting of carbon, hydrogen, oxygen, nitrogen, and sulfur was…

A: Given, mass of 2.86 g sample of a compound produced 1.61 g CO2 and 0.989 g H2O.Moles of CO2 and H2O…

Q: A strikingly beautiful copper compound with the common name “blue vitriol” has the following…

A: Since the compound is having Cu, S, H and O hence we can say that the empirical formula of compound…

Q: A metal has the mass  of 12.00 g and 5.850 x 1022 atoms.  Calculate molar mass of the metal.

A: Formula use is, no of moles = weight/ molar mass

Q: An organic compound contains 24.24 % Carbon, 4.04 % Hydrogen, and 71.72 % Chlorine. What is its…

A: Given, Mass % of carbon (C) = 24.24 % = 24.24 g Mass % of hydrogen (H) = 4.04 % = 4.04 g Mass % of…

Q: A 0.5998-g sample of a new compound has been analyzed and found to contain the following masses of…

A: Given, mass of sample of compound = 0.5998 g The sample contains, mass of Carbon (C) = 0.2322 g mass…

Q: When 5.347 grams of a hydrocarbon, C,Hy, were burned in a combustion analysis apparatus, 16.38 grams…

A: Empirical formula can be determined from the moles of gases formed of CO2 and H2O

Q: a compound contains 47.08% C, 6.59% Hydrogen and 46.33% Cl by mass. The molar mass of the compound…

A: T

Q: What is the formula for the compound ?

A: The percent composition of an organic compound provides information about the percent/gram of each…

Q: Part D. A 28.50 g sample of a compound of carbon, sulfur, hydrogen, and combusted (burned). 35.25 g…

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Q: Combustion of 2.16 g of an unknown compound containing only carbon, hydrogen, and nitrogen produces…

A: To determine the empirical formula , we need to calculate the moles of carbon, hydrogen and nitrogen…

Q: osmium by mass. a) If you assume 100.0 g of the compound, what is the mass in grams of osmium that…

A: Since you have posted a question with multiple sub- parts, we will solve first three sub- parts for…

Q: empirical and molecular formula of the compound

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Q: is trying to discover information about an unknown metal in a compound. The formula for the compound…

A: Atomic mass of an element is the mass of an atom of the element.Here we have to calculate atomic…

Q: Chemical analysis of a asprin tablet determined that it was composed of 57.7% carbon, 37.5% oxygen…

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Q: The empirical formula of a compound is C8H5N3O5. The compound has a molar mass of 892.6 g/mol;…

A: Molecular formula: In a molecular formula we describe the number of atoms of all the elements…

Q: When 4.876 grams of a hydrocarbon, C,H,, were burned in a combustion analysis apparatus, 15.30 grams…

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Q: You determine the empirical formula of a compound to be CH3. In a separate experiment, you determine…

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Q: A compound's empirical formula is ‎C4H8O. If the molar mass is 288.5 g/mol, what is the molecular…

A: We have to predict the molecular formula of the compound.

Q: A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of the compound yields…

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Q: A sulfide of iron is produced when 2.33 g of iron reacts with 1.926 g of sulfur. What is the…

A: Empirical formula of a compound represents the simplest whole number ratio of the moles of the…

Q: Imagine you discover a substance in a forest mushroom and find through experimentation that it…

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Q: experiment, 3.15 g of this compound  was combusted to produce 5.69 g of CO2 , 2.72 g H2O and 0.734 g…

A: Moles of C = 5.69/44 = 0.129 mol Mass of C = 0.129×12 = 1.55 g Moles of H = 2.72×2/18 = 0.302 mol…

Q: 2. A mixture weighing 1.250 grams is 20.0% sodium nitrate, 56.0% silicon dioxide, and the rest is…

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.