Related questions
Question
HI, Please see attached image for question. Thank you
Transcribed Image Text:A 65kg bicyclist (including the bicycle), initially at rest at
the top of a hill, coasts down the hill, reaching a speed
of 15.5m/s at the bottom of the hill. The distance and
height of the hill are shown. Neglect any friction
impeding the motion and the rotational energy of the
wheels.
List the energy types at the initial and final time and whether work
60m
and loss (due to non-conservative forces) occur as well as the
19m
corresponding amounts of energy.
reference level
initial: GPE
? Noworke
work?
%3D
vsand = 343 ms
loss?
Loss •
final: KE o
7808 1
What was the strength of the drag?
cannot be determined
check answers
%3D
<>
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution
Trending nowThis is a popular solution!
Step by stepSolved in 2 steps
Knowledge Booster
Similar questions
- Please solve this problem using two approaches: a) Draw a ray diagram to locate the image b) Use the mirror & magnification equations to calculate the image distance (di) and image height (hi) (show your work)arrow_forwardA converging lens such as a magnifying glass has a radius of curvature of 14.6 cm. A letter in a book under this magnifying glass appears 3 times larger than its actual size. If the image is upright. how many centimeters is the book from, the magnifying glass? Please round your answer to one decimal place.arrow_forwardStudent # S= Object Distance (cm) P= Image Distance (cm) F= Focal Length from Lens Formula (cm) 1 12 60 ? 2 14 35 ? 3 20 20 ? The form of the Lens formula used most commonly in physics is (1/p) + (1/s) = 1/f p= image distance s= object distance f= focal length 1. calculate the focal length for each of the combinations of s and p by use of the lens formula. average focal length: 2. use the lens formula to derive an equation that gives p in terms of s and f.arrow_forward
- You place your friend 75 cm away from a convex mirror with a focal length of -1.5 meters. What does a diagram of this look like including the focal point, focal length, and person?arrow_forwardThe radius of the curvature for a converging mirror is 36 cm. What is its focal length, in cm? Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.arrow_forwardIn the figure, the thin lens forms a real image of the object 94.0 cm from the object. What is the focal length of the lens? 9.70 mm Object 35.0 cm- Thin Lensarrow_forward
- If the distance of the object is 250 cm and the distance of the image is 140 cm, I say that the focal length is 390 cm. true or falsearrow_forwardThe virtual image produced by a convex mirror is one fifth the size of the object. If the object is 30.9 cm in front of the mirror, what is the image distance? 10.3 cm Submit Answer Incorrect. Tries 1/5 Previous Tries What is the focal length of this mirror? Submit Answer Tries 0/5arrow_forwardWhat factor indicates if an image is upright or inverted?arrow_forward
- The image with the diagram serves as a reference for the second image with the actual question. Please answer the question on the image without the diagram.arrow_forwardAn object is 30cm from 15 cm focal length lens. Where is the image? Draw image by using ray diagram.arrow_forwardPlease see the image attached. I only need part D. Thank you so much!arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios