A 63 kg diver stands at the end of a 31 kg springboard, as shown in the figure. The board is attached to a hinge at the left end but simply rests on the right support.(Figure 1)What is the magnitude of the vertical force exerted by the hinge on the board? This image illustrates a simple physics concept related to balance and fulcrums. It depicts a plank supported by two triangular fulcrums and a person standing on one end of the plank. - The plank is horizontal.- The left fulcrum is located 1.5 meters from the left end of the plank.- The right fulcrum is positioned 3.0 meters from the left fulcrum.- A person is standing at the far right end of the plank.This setup is often used in physics to explain concepts of torque and equilibrium, where the balance of forces and moments around a pivot is studied.

By the given situation the vertical force applied by the hinge will be to balance the spring board. Now taking right support as the axis of rotation by the symmetry the weight of the board is at the middle acting downward and the force by the weight of the diver at the right end is downward let the force on board by the hinge is F so by equilibrium condition the net moment will be zero about the right support so F(1.5 m)+mbg(0)+(1.5 m)mdg = 0F(-1.5 m)+(31 kg)(9.81 m/s2)0+ (63 kg)(1.5 m)(9.81 m/s2) = 0 F = 9271.5 N = 618 N so the force exerted by the hinge on the board is F = 618 N downward thank you!