College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A 600pF capacitor is charged by a 200V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. How much electrostatic energy is lost in the process?
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- A 80-pF capacitor and a 320-pF capacitor are both charged to 1.70 kV. They are then disconnected from the voltage source and are connected together, positive plate to negative plate and negative plate to positive plate. (a) Find the resulting potential difference across each capacitor. V 80 pF = 1.02 kV V 320 pF = 1.02 kV (b) Find the energy lost when the connections are made. 3.7*10**6arrow_forward(a) A 2.75 uF capacitor and a 3.25 uF capacitor are connected in series across a 8,50 V battery. How much charge (in uC) is stored on each capacitor? 2.75 µF capacitor 3.25 µF capacitor (b) The same two capacitors are disconnected and discharged. They are then connected in parallel across the same battery. How much charge (in µC) is stored on each capacitor now? 2.75 µF capacitor 3.25 µF capacitor O Show My Work (Optional) ?arrow_forwardTwo identical parallel-plate capacitors, each with capacitance 15.5 F, are charged to potential difference 46.0 V and then disconnected from the battery. They are then connected to each other in parallel with plates of like sign connected. Finally, the plate separation in one of the capacitors is doubled. (a) Find the total energy of the system of two capacitors before the plate separation is doubled. (b) Find the potential difference across each capacitor after the plate separation is doubled. (c) Find the total energy of the system after the plate separation is doubled. (d) Reconcile the difference in the answers to parts (a) and (c) with the law of conservation of energy. O Positive work is done by the agent pulling the plates apart. Negative work is done by the agent pulling the plates apart. No work is done by pulling the agent pulling the plates apart.arrow_forward
- (a) A 2.00 uF capacitor and a 6.50 uF capacitor are connected in serles across a 3.00 V battery. How much charge (In uc) Is stored on each capacitor? 2.00 µF capacitor 6.50 pF capacitor (b) The same two capacitors are disconnected and discharged. They are then connected in parallel across the same battery. How much charge (in pC) is stored on each capacitor now? 2.00 UF capacitor 6.50 µF capacitor Need Help? Rend Itarrow_forwardA 4.50 pF capacitor is connected in series with a 3.00 pF capacitor and a 350 V potential difference is applied across the pair. (a) What is the charge on each capacitor (in nC)? 4.50 pF саpасitor 6.3e-10 X nC 3.00 pF сараcitor 6.3е-10 X nC (b) What is the voltage across each capacitor (in V)? 4.50 pF сараcitor V 3.00 pF сараcitor Varrow_forward(a) A teaching assistant connects a 8.00 V battery to the plates of a capacitor. After waiting a while, the capacitor reaches a maximum amount of 33.0 µC of stored charge. What is the value of the capacitance (in µF)? μF (b) The capacitor is disconnected from the battery, discharged, and then connected to a 20.0 V battery. Again, a long enough time is waited for the capacitor to fully charge. How much charge (in µC) is stored now? (Assume the capacitor can handle this new voltage without failing.) μεarrow_forward
- An initially uncharged air-filled capacitor is connected to a 3.29 V charging source. As a result, the capacitor acquires 9.89 x 10- C of charge. Then, while the capacitor remains connected to the charging source, a sheet of dielectric material is inserted between its plates, completely filling the space. The dielectric constant k of this substance is 7.61. Find the voltage V across the capacitor and the charge Qf stored by it after the dielectric is inserted and the circuit has returned to a steady state. V = V Qt = Carrow_forwardTwo identical parallel-plate capacitors, each with capacitance 17.0 ?F, are charged to potential difference 48.5 V and then disconnected from the battery. They are then connected to each other in parallel with plates of like sign connected. Finally, the plate separation in one of the capacitors is doubled. (b) Find the potential difference across each capacitor after the plate separation is doubled. (c) Find the total energy of the system after the plate separation is doubled.arrow_forwardIn the figure below, capacitor 1 (C₁ 29.0 μF) initially has a potential difference of 59.0 V and capacitor 2 (C₂ = 6.00 μF) has none. The switches are then closed simultaneously. C₁ = = C₂ (a) Find the final charge on each capacitor after a long time has passed. Q1 C с (b) Calculate the percentage of the initial stored energy that was lost when the switches were closed. %arrow_forward
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