A 6 kg bowling ball moving at 9.5 m/s collides with a 0.62 kg bowling pin, which is scattered at an angle of 84.5° to the initial direction of the bowling ball and with a speed of 13 m/s. Calculate the final velocity of the bowling ball. For the direction, give the absolute value of the angle relative to the initial direction of the of the bowling ball. Magnitude: m/s Direction: degrees Calculate the ratio of the kinetic energy after the collision to the kinetic energy before the collision. Is the collision elastic? ?

A 6.75-kg bowling ball moving at 8.95 m/s collides with a 0.875-kg bowling pin, which is scattered at an angle of θ = 24.5° from the initial direction of the bowling ball, with a speed of 11.2 m/s. Calculate the magnitude of the final velocity, in meters per second, of the bowling ball.

In a 2D elastic collision two balls collide (see picture). The 1st balls mass is 50g. It has an initial velocity of 6m/s. The 2nd balls mass is 125g. It has an initial velocity of 0m/s. The 1st ball has a final velocity of 5 m/s and an angle ? = 45°. Find the velocity of the second ball and it’s angle ?.

52. The Center of Mass of Sulfur Dioxide Sulfur dioxide (SO₂) consists of two oxygen atoms (each of mass 16 u, where u is defined in Problem 40) and a single sulfur atom (of mass 32 u). The center-to-center distance between the sulfur atom and either of the oxygen atoms is 0.143 nm, and the angle formed by the three atoms is 120°, as shown in Figure 9-20. Find the x and y coordinates of the center of mass of this molecule. Oxygen 0.143 nm y 120° Oxygen 0.143 nm Sulfur A FIGURE 9-20 Problem 52 I

Question 6. A diagram of the collision between a moving cue ball and an initially stationary eight ball on a billiards table is given below. The collision of the billiards balls can be considered an isolated system. W- N por Cue ball y = 4.00 m/s m = 0.180 kg p = 0.720 kg-m/s V 2/1 Apple 1₂V/2 0 DALO TO 4MB x V q Determine the velocity of the cue ball immediately after the collision. x 000000 m = 0.180 kg Eight ball O +0 40° ********** Question 7. Classify the collision above as elastic, inelastic or super elastic. dlad V = 3.20 m/s m = 0.160 kg p=0.512 kg-m/s AYP SOL CANDIDA * 12 2 no thouse 52

During a fireworks display, a 0.280-kg bottle rocket approaches the top of its trajectory and explodes into two pieces as in the figure. The first piece (Piece 1) has mass 0.180 kg and the second piece (Piece 2) has mass 0.100 kg. Immediately after the explosion, the first piece is observed traveling to the left at a speed of4.30 m/sand the second piece is observed traveling at an angleθ = 39.0°above the horizon at a speed of 17.0 m/s.   Determine the components of the bottle rocket's velocity immediately before the explosion. Vxi  =    m/s Vyi  =    m/s

A 8.0kg puck floating on an air table is traveling east at 10cm/s. Coming the other way at 30cm/s is a 2.0kg puck on which is affixed a wad of bubble gum.The two slam head-on into each other and stick together. a) Find their velocity after the impact.b) How much kinetic energy is lost?

Problem B) An inelastic collision occurs between a particle of mass 1.5 kg moving with an initial velocity of v = (-2i – 1.33 + 0.7k) m/s and another particle of mass 0.8 kg that has an initial velocity of v = (5.6å + 0.53 + 4.3k) m/s. What is the final velocity of the particles in unit vector notation? %3D