A 5.80-kg bowling ball moving at 8.70 m/s collides elastically with a 0.680-kg bowling pin, which is scattered at an angle θ₁ = 25.8° to the initial direction of the bowling ball and with a speed of 7.70 m/s. Calculate the final (a) speed and (b) direction (magnitude and direction θ₂, measured from initial direction of the bowling ball) of the bowling ball.- Magnitude: 6.76 m/s- Direction: 8.24°This problem involves an elastic collision, which conserves both kinetic energy and momentum. The task is to determine the final speed and direction of the bowling ball after the collision.

Answered: A 5.80-kg bowling ball moving at 8.70…

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A 5.80-kg bowling ball moving at 8.70 m/s speed of 19.0 m/s. Calculate the final veloci = 6.76 m/s Magnitude Directi

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

A 5.80-kg bowling ball moving at 8.70 m/s collides elastically with a 0.680-kg bowling pin, which is scattered at an angle θ₁ = 25.8° to the initial direction of the bowling ball and with a speed of 7.70 m/s. Calculate the final (a) speed and (b) direction (magnitude and direction θ₂, measured from initial direction of the bowling ball) of the bowling ball.

- Magnitude: 6.76 m/s
- Direction: 8.24°

This problem involves an elastic collision, which conserves both kinetic energy and momentum. The task is to determine the final speed and direction of the bowling ball after the collision.

Expert Solution

Step 1

accordinmg to newtons law

a system's momentum cannot be changed until force is applied on the system

if no force is applied on system then initial momentum of system equals to final momentum of system

momentum is defined as m x v

where m = mass of body

v = velocity of body

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