A 5V dc stabilized power supply needed to operate a computer is to be produced from a 12V full-wave bridge rectifier using a Zener diode as the regulator circuit. The maximum power rating of the zener diode , Pz is 6W. Calculate the following Maximum current flowing through the zener diode. Value of the series current limiting resistor, Rs. ii. Load current, lc if the load resistor is 50kΩ

A 5V dc stabilized power supply needed to operate a computer is to be produced from a 12V full-wave bridge rectifier using a Zener diode as the regulator circuit. The maximum power rating of the zener diode , Pz is 6W. Calculate the following Maximum current flowing through the zener diode. Value of the series current limiting resistor, Rs. ii. Load current, lc if the load resistor is 50kΩ

Electric Motor Control

10th Edition

ISBN:9781133702818

Author:Herman

Publisher:Herman

Chapter59: Motor Startup And Troubleshooting Basics

Section: Chapter Questions

Problem 12SQ: How is a solid-state diode tested? Explain.

See similar textbooks

Similar questions

What is the difference between a diode and rectifier?
How is a solid-state diode tested? Explain.
A full-wave rectifier uses 2 diodes. The internal resistance of each diode is 20 Q. The transformer RMS secondary voltage from centre tap to each end of the secondary is 50 V and the load resistance is 980 Q. Mean load current will be
A single-phase full-wave bridge rectifier circuit is fed from a 220 V, 50 Hz supply. It consists of four diodes, a load resistance 20 Q and a very large inductance so that the load current is constant. What is the average or dc output voltage?
3 Given the bridge-type full-wave rectifier circuit shown 220V 60Hz 220V:Es Es D1 D2 D3 D4 The load resistor is 220 and the transformer average current is 300mA. Determine: (a) Average value, RMS value, and frequency of load voltage VRL. (b) Average current and PIV of each diode. RL
A full wave bridge rectifier is supplied from 230V, 50Hz and uses a transformer of turns ration 15:1. It uses load resistance of 50 ohms. Calculate load voltage and ripple voltage. Assume ideal diode and transformer. Assume ripple factor equals to 0.482. a.Load Voltage= 13.8 V; Ripple Voltage=6.652 V b.Load Voltage= 15.6 V; Ripple Voltage=7.611 V c.Load Voltage= 21.3 V; Ripple Voltage=8.410 V d.Load Voltage= 25.1 V; Ripple Voltage=10.442 V
Create a Half-Wave Rectifier circuit. Use a resistor of 1000 Ohms. Input Voltage should be 95VAC - 65Hz Plot both the Input voltage and output voltage. Determine the Voltage drop across the diode by subtracting the output voltage to the input voltage peaks. Create a Bridge-Type Full Wave Rectifier Circuit. Repeat the steps done on the Half-Wave Rectifier circuit.
In a full wave bridge rectifier, the transformer secondary voltage is 20sinwt. The forward resistance of each diode is 20N and load resistance is 1.5K. Calculate, i. Im ii. Ide
8 5. In a single-phase diode bridge rectifier circuit fed by a source voltage of 240 50%THD and a fundamental of 10A(rms). The power drawn is 2kW, Calcu a) The DPF b) The distortion current Idistortion c) The total current Is J The PF
Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V rmsh soHz} VL-DC =20V 0.01 F 0.02 F 0.0167 F None of the above
When the rms output voltage of a bridge full-wave rectifier is 20 V. the peak inverse voltage across the diodes is (neglecting the diode drop)
Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V ams 5OHZ İL-DC =05A RL VL-DC =20V