A 50 kg box is pushed with a force of 200 N along a horizontal surface. If the coefficient of friction between the box and the surface is 0.3, calculate the acceleration of the box. (Note: The gravitational acceleration can be assumed to be 9.8 m/s² unless stated otherwise.)

A 50 kg box is pushed with a force of 200 N along a horizontal surface. If the coefficient of friction between the box and the surface is 0.3, calculate the acceleration of the box. (Note: The gravitational acceleration can be assumed to be 9.8 m/s² unless stated otherwise.)

Name: A 50 kg box is pushed with a force of 200 N along a horizontal surface
Uploaded: 2024-03-20T06:56:46.000Z
Channel: Bartleby
Description: A 50 kg box is pushed with a force of 200 N along a horizontal surface. If the coefficient of friction between the box and the surface is 0.3, calculate the acceleration of the box.(Note: The gravitational acceleration can be assumed to be 9.8 m/s² u

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: More Applications Of Newton’s Laws

Section: Chapter Questions

Problem 5OQ

See similar textbooks

Similar questions

A black widow spider hangs motionless from a web that extends vertically from the ceiling above. If the spider has a mass of 1.5 g, what is the tension in the web?
A crate is pushed across a horizontal surface by the applied force shown in the figure. The magnitude of the force F = 24.1 N, 0 = 27.9°, the coefficient of kinetic friction between the block and the surface is 0.4, and M = 2.49 kg, what is the magnitude of the acceleration of the crate in m/s?
A 50.7 kg box is resting on a horizontal floor. A force of 317.1 N directed at an angle of 34.1° below the horizontal is applied to the box. The coefficient of static friction between the box and the surface is 0.5, and the coefficient of kinetic friction is 0.2. The force of friction on the box is:
The coefficient of kinetic friction between a box and the floor is u, = 0.16 and the coefficient of static friction is u, = 2.0µ. (a) Calculate the ratio of static to kinetic friction force if m = 9 kg. (b) Will the ratio change if the value of m is changed but u, still equals 2.0µ? Yes No
A snowboarder and his board with a combined mass of 50.0 kg moving at 9.50 m/s are about to go up an incline of angle 34.9 degrees, but due to friction only make it up a vertical height of 2.00 m. What was the coefficient of friction?
A block with a mass m is pushed up an inclined rough surface by a horizontal force F as shown. If the block is being pushed up at a constant speed, find the magnitude of the applied force F, given that theta =35 degrees , m = 5 kg, and the kinetic frictional coefficient between the block and the inclined surface mu_k = 0.2
A block of mass 8.3 kg is initially at rest on a horizontal plane. The coefficients of kinetic and static friction between the plane and the block are respectivelyμc= 0.25 and μe= 0.36. Consider g = 10 m/s2 A horizontal force of magnitude F = 26.3 N is then applied to the block. In this situation, calculate the magnitude of the friction force (in N, to one decimal place).
You are trying to slide a sofa across a horizontal floor. The mass of the sofa is 2.0 x 102kg, and you need to exert a force of 3.5 x 102N to make it just begin to move. (a) Calculate the coefficient of static friction between the floor and the sofa.(b) After it starts moving, the sofa reaches a speed of 2.0 m/s after 5.0 s. Calculate the coefficient of kinetic friction between the sofa and the floor.
A passenger is standing on a scale in an elevator. The building has a height of 500 feet, the passenger has a mass of 80 kg, and the scale has a mass of 7 kg. The scale sits on the floor of the elevator. (It is an Otis elevator, so we will label it as "O" so as not to confuse its forces with those caused by the earth.) You may take g = 10 N/kg. For doing this problem it might be useful to start by drawing free-body diagrams for the passenger and the scale. Consider the vertical forces acting on the passenger and the scale WE→P: The force of the earth pulling down on the passenger (weight). WE→S: The force of the earth pulling down on the scale (weight). NP→S: The force of the passenger pushing down on the scale (normal). NS→P: The force of the scale pushing up on the passenger (normal). NO→S: The force of the elevator pushing up on the scale (normal). NO→P: The force of the elevator pushing up on the passenger (normal). Which of these forces affect the motion of the passenger? Select…
A passenger is standing on a scale in an elevator. The building has a height of 500 feet, the passenger has a mass of 80 kg, and the scale has a mass of 7 kg. The scale sits on the floor of the elevator. (It is an Otis elevator, so we will label it as "O" so as not to confuse its forces with those caused by the earth.) You may take g = 10 N/kg. For doing this problem it might be useful to start by drawing free-body diagrams for the passenger and the scale. a) The elevator now begins to descend. Starting from rest, it takes the elevator 6 seconds to get up to its downward speed of 12 m/s. Assuming that it is accelerating downward at a uniform rate during these 6 seconds, what is the acceleration? b) While it is accelerating downward, what does the scale read (in newtons)?
You are pushing a box, apply Fa = 90 N. The box's mass is 25 kg. The coefficients of friction are μs =0.60 and μk = 0.4. The box was stationary when you began pushing. Calculate the frictional force magnitude exerted on the box by the floor
A rope exerts a force of 50 N on a box to keep it stationary. If the box is on a plane inclined 25° from the horizontal and the coefficient of static friction is 0.29, calculate the normal force exerted on the box.