A 50 Hz sinusoidal AC voltage source of peak value V, = 340 V delivers power to a resistive load of 50 n. (c) (i) Calculate the average power delivered.

QUESTION 1 What is the RMS value of an AC voltage that has a 347 V peak? a. 245.3 b.490.6 Oc. 265.7 Od.469.3 QUESTION 2 What is the peak value when an RMS voltage is 245 volts? Oa. 346.43 Ob.173.2 Oc. 396.5 d. 189.4 Cick S

write b , c and d

Let voltage across a load be v(t) = 20 + 40 cos(100t) volt and current through the load by i(t) = 1-0.5 sin(100t) ampere. RMS value of the voltage is volt Watt Average power dissipated in the load is

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A 3-phase induction motor delivers 74,600 watts while operating at an efficiency of 80 percent and a power factor of 0.75 lagging from a 480 V source. Determine the value of capacitance required per phase to improve the overall power factor to 0.9 lagging.

b) Referring to Figure 6, given that the peak voltage Vp = 24 v. Determine: i. The period, T ii. The frequency, f. iii. The angular velocity, w. iv. The voltage, VRMS V. Write the mathematical expression for the sine wave in Figure 6 to represent the ac voltage. c) Determine the instantaneous voltage at: i. t = 10 µs. i. t = 70 µs v(t) 75 175 t (us) 125 Figure 6

The rms current in a 33.0-0 resistor connected to an AC source is 2.80 A. (a) What is the rms voltage across this resistor? V (b) What is the peak voltage of the AC source? V (c) What is the average power dissipated by the resistor? W (d) What is the maximum current across this resistor? A

Q2. For the circuit shown below, sketch the current waveforms is and io and determine the Average and RMS for both currents. a = 50° T1 50 2 ot Vs = 300 sin 100rt T2 ot