A 5.510 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is u, = 0.605 and the coefficient of kinetic friction is µk = 0.205. At time t = 0, a force F = 20.1 N is applied m horizontally to the block. State the force of friction applied to the block by Us,k the table at times t = 0 and t > 0. 32.67 11.07 t = 0 N t > 0 N Incorrect Incorrect Consider the same situation, but this time the external force F is 40.6 N. Again, state the force of friction acting on the block at times t = 0 and t > 0. t = 0 32.67 N t > 0 11.07 N

A 2.220 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is µs = 0.605 and the coefficient of kinetic friction is µ = 0.255. At time t = 0, a force F = 8.10 N is m Us,k applied horizontally to the block. State the force of friction applied to the block by the table at times t = 0 and t > 0. t = 0 N t > 0 N Consider the same situation, but this time the external force F is 16.3 N. Again, state the force of friction acting on the block at times t = 0 and t > t = 0 N t > 0 N * TOOLS x10

Determine two force members first. Two blocks are each pin connected to a massless horizontal link. Determine the largest P before motion cocurs. Use 0.35 and 0.3 for the friction coefficients. 45° J c 4.5 kg 3 kg B 30°

PART A) What is the maximum force that can be applied to a bone whose minimum cross-sectional area is 3.0cm^2? (This is approximately the cross-sectional area of a tibia, or shin bone, at its narrowest point.) Express your answer using two significant figures.        PART B)  Estimate the maximum height from which a 70kg man could jump and not fracture the tibia. Take the time between when he first touches the floor and when he has stopped to be 0.006s, and assume that the stress is distributed equally between his legs. Express your answer using two significant figures.         Thank you!!!