A 5.0 kg cat and a 2.0 kg bowl of tuna fish are at opposite ends of a 4.0 m long seesaw. How far to the left of the pivot point must a 4.0 kg cat stand to keep the seesaw balanced? 5.0 kg 4.0kg 2.0 kg d A 2.0 m 2.0 m Pivot

A 5.0 kg cat and a 2.0 kg bowl of tuna fish are at opposite ends of a 4.0 m long seesaw. How far to the left of the pivot point must a 4.0 kg cat stand to keep the seesaw balanced? 5.0 kg 4.0kg 2.0 kg d A 2.0 m 2.0 m Pivot

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter8: Rotational Equilibrium And Dynamics

Section: Chapter Questions

Problem 34P

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A 5.0 kg cat and a 2.0 kg bowl of tuna fish are at opposite ends of a 4.0 m long seesaw.
How far to the left of the pivot point must a 4.0 kg cat stand to keep the seesaw balanced?
5.0 kg
4.0kg
2.0 kg
d A
2.0 m
2.0 m
Pivot
Anint
5.

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