A 53−kg person drinks5.4×102g of milk, which has a caloric value of approximately 3.0 kJ/g.If only 17 percent of the energy in milk is converted to mechanical work, how high (in meters) can the person climb based on this energy intake? Enter your answer in scientific notation. Hint: The work done in ascending is given by mgh, where m is the mass (in kg), g is the gravitational acceleration(9.8 m/s2), and h is the height (in meters).

A 53−kg person drinks5.4×102g of milk, which has a caloric value of approximately 3.0 kJ/g.If only 17 percent of the energy in milk is converted to mechanical work, how high (in meters) can the person climb based on this energy intake? Enter your answer in scientific notation. Hint: The work done in ascending is given by mgh, where m is the mass (in kg), g is the gravitational acceleration(9.8 m/s2), and h is the height (in meters).

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter1: Getting Started

Section: Chapter Questions

Problem 48PQ: In 2011, artist Hans-Peter Feldmann covered the walls of a gallery at the New York Guggenheim Museum...

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We are now able to define a mathematical formula for gravitational potential energy. Near the Earth's surface, the gravitational potential energy of a system consisting of the earth and an object with a mass m is EP = mgh, where g is the acceleration of gravity (9.80 m/s2) and h is the height above ground level (positive upward). Note that the "ground level" could really be any height we choose, because what's really important is the change in potential energy. The difference between two heights always gives the same change in potential energy, regardless of where we set the "zero" of height. In other words, if we find the change in potential energy ΔEP = EP,f − EP,i, the final potential energy minus the initial, we have ΔEP = mghf − mghi = mgΔh. The change in gravitational potential energy is just mg times the change in height. Let's return to our ball-Earth example, only now let's examine a case where a ball is rising in the air. You toss a ball with a mass of 0.703 kg upward.…