A 41.1 kg sled coasts down a hill, starting from rest. The hill is inclined at an angle of 25.9 degrees with respect to the horizontal and has a height of 10.8 m. The coefficient of kinetic friction between the sled's blades and the hill is ??μs = 0.13. What is the work done on the sled (in Joules) by the gravitational (or weight) force as the sled coasts from the top of the hill to the ground? Use g = 9.81 m/s2.

The figure below shows three forces applied to a trunk that moves leftward by 1.3 over a frictionless floor. The force magnitudes are F1=5.00 N, F2 = 6.00 N, and F3 = 3.00 N, and the indicated angle is theta= 60.0 degrees.  During the displacement, what is the net work done on the trunk by the three forces. (Answer in Joules)

One boat tows another boat by means of a tow line, which is under a constant tension of 465 N. The boats move at a constant speed of 4.60 m/s. How much work is done by the tension in 1.10 min?

A 4.8 kg body is at rest on a frictionless horizontal air track when a constant horizontal force F acting in the positive direction of an x axis along the track is applied to the body. A stroboscopic graph of the position of the body as it slides to the right is shown in the figure. The force is applied to the body at t = 0, and the graph records the position of the body at 0.50 s intervals. How much work is done on the body by the applied force between t = 0 and t = 1.5 s? = 0 0.5 s -1.0 s 1.5 s 2.0 s 0 0.2 0.4 x (m) 0.6 0.8

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a mass of 4.5× 104 kg, and the force causes its speed to change from 7400 to 5600m/s. (a) What is the work done by the force? (b) If the asteroid slows down over a distance of 2× 106 m determine the magnitude of the force.

A person pushes a 16.0-kg shopping cart at a constant velocity for a distance of 22.0 m. She pushes it in the direction 30.0° below the horizontal. A 48.0-N frictional force opposes the motion of the cart. (a) Draw the free-body diagram showing the forces that act on the cart. (b) What is the magnitude of the force that the shopper exerts? Determine the work done by (c) the pushing force, (d) the frictional force, and (e) the gravitational force. Step 1 Incorrect. (a) Draw the free-body diagram showing the forces that act on the cart. Use the checkboxes to select the correct vectors as instructed above. Move the vectors to the correct starting points and orient them in the correct direction as instructed. mg Key to Force Labels mg = Gravitational force Fx = Spring force FN = Normal force T = Tension f = Frictional force Fp = Push force mg F. Fp FN T Draw free-body diagram here

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a mass of 4.7× 104 kg, and the force causes its speed to change from 7300 to 5300m/s. (a) What is the work done by the force? (b) If the asteroid slows down over a distance of 1.6× 106 m determine the magnitude of the force.

A raft is being dragged along a channel by two chains dragged to the right. The tension in each chain is T =10 kN and each chain is being pulled at an angle of θ = 200 relative to the direction of motion. How much work will be done in pulling this raft a distance of 4.0 km?

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a mass of 5.8× 104 kg, and the force causes its speed to change from 6700 to 5100m/s. (a) What is the work done by the force? (b) If the asteroid slows down over a distance of 2.1x 106 m determine the magnitude of the force. (a) Work = (b) F = 260000 i -5470

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a mass of 4.2x 104 kg, and the force causes its speed to change from 7500 to 5000m/s. (a) What is the work done by the force? (b) If the asteroid slows down over a distance of 1.7x 106 m determine the magnitude of the force. (a) Work= (b) F= i i