A 2300/230 V distribution transformer is delivering a load of 50kW to a certain part of a community. If the total wire impedance is 0.5, what power is actually delivered
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A 2300/230 V distribution transformer is delivering a load of 50kW to a certain part of a community. If the total wire impedance is 0.5, what power is actually delivered?
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- For an ideal transformer, the efficiency is (a) 0 (b) 100 (c) 50All values of a transformer are proportional to its __________________ ___________________.For a short-circuit test on a 2-winding transformer, with one winding shorted, can you apply the rated voltage on the other winding? (a) Yes (b) No
- 6. The figure below shows a single-line-diagram of part of a power system. For each transformer in the diagram state a suitable connection method, giving reasons for your suggested connection method. G1 G1 800MW 200MW 15kV 10kV T1-T4 88 T5-T6 250MVA each 125MVA each 330/15kV 88/10kV Line 1 Line 2 T7-T8 100MVA each 330/88kV T9 T10-T11 50MVA 50MVA each 88/66kV 88/11kV T12 2MVA 11/0.4kV Singe-phase loadsDetermine the equivalent impedances circuit referred to the primary side of a 20- kVA, 8000/240 V, 60 Hz transformer. The open circuit test was performed on the secondary side and the short circuit test was performed on the primary side. (on secondary) Open-circuit test Short-circuit test (on primary) Voc = 240 V VSC = 489 V loc = 7.133 A Isc = 2.5 A Voc = 400 W Psc = 240 WA 1000-VA, 230/115-V transformer has been tested to determine its equivalent cir- cuit. The results of the tests are shown below. Open-circuit test (on secondary side) Short-circuit test (on primary side) Voc = 115 V Vsc = 17.1 V %3D %3D Isc 8.7 A Psc loc =0.11 A Poc = 3.9 W = 38.1 W (a) Find the equivalent circuit of this transformer referred to the low-voltage side of the transformer. (b) Find the transformer's voltage regulation at rated conditions and (1) 0.8 PF lag- ging, (2) 1.0 PF, (3) 0.8 PF leading. (c) Determine the transformer's efficiency at rated conditions and 0.8 PF lagging.
- The equivalent circuit impedances of a single phase 10-KVA, 480/120 V, 60 Hz transformer are to be determined. The open circuit and short circuit test results as performed on the primary side is as follows. 1. Open-circuit test Short-circuit test Voc = 480 V loc = 0.41 A Poc = 38 W Vsc = 10.0 V Isc = 10.6 A Psc = 26 W %3D %3D %3D %3D a) Find the impedances of the approximate transformer equivalent circuit referred to the primary side, and sketch the circuit. b) What are the impedances when referred to the secondary side. Sketch the resulting circuit.In the circuit in Figure 2, the capacitor connected to the a-b terminals of the transformer anda circuit consisting of resistance is defined as a load circuit. a)Find the average power spent by the load circuit? b) How much of the average power calculated in a) by the resistance in the load circuit and how muchspent by the capacitor? Comment on the results obtained?Assignment 3 A 15-KVA, 2400/240-V transformer is to be tested to determine its excitation branch components, its series impedances and its voltage regulation. The following test data have been taken from the primary side of the transformer: Short-circuit test Open- circuit test Voc = 2400 V loc = 0.25 A Poc = 50 W Vsc = 48 V Isc = 6.0 A Psc = 200 W Pg103 The data have been taken by using the connections of open-circuit test and short-circuit test a. Find the equivalent circuit of this transformer referred to the high-voltage side. b. Find the equivalent circuit of this transformer referred to the low-voltage side. c. Calculate the full-load voltage regulation at 0.8 lagging power factor and 0.8 leading power factor. d. What is the efficiency of the transformer at full load with a power factor of 0.8 lagging?
- 2. A 2000-VA 230/115-V transfornmer has been tested to determine its equivalent circuit. The results of the tests are shown below. Open-circuit test Voc = 230 V Ioc = 0.45 A Poc= 30 W Short-circuit test Vsc = 13.2 V Isc = 6.0 A Psc=20.1 W All data given were taken from the primary side of the transformer. (a) Find the equivalent circuit of this transformer referred to the low-voltage side of the transformer. (b) Find the transformer's voltage regulation at rated conditions and (1) 0.8 PF lagging, (2) 1.0 PF, (3) 0.8 PF leading. (c) Determine the transformer's efficiency at rated conditions and 0.8 PF lagging.A single-phase, 240 kVA, 240/4800 V transformer has the parameters shown in Figure Q5. Determine I and V at the primary and secondary when transformer is operating at full load kVA, 0.8 power factor leading and 220 V at the primary side. Find the voltage regulation. Use actual values and per unit system. 0.002625 Q 0.009 0 1.05 Ω 3.6 Ω V2 40 0 30 Q Figure Q5The rated voltages of a single-phase transformer are 2000 V and 200 V in its primary and secondary respectively. The shunt impedance can be modelled with a resistance of 14000 ohms in parallel with a reactance of 1100 ohm, both refer to primary side. The primary and secondary series impedances are (0.12+j 0.35) ohms and (0.0012+j 0.0035) ohms respectively. A load is connected to the secondary side of transformer, draws 810 KVA with a lagging power factor of 0.85. The load voltage is same as rated voltage, that is 200 V. ▪ Use per unit method for analysis and find the voltage on primary side in pu.