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College Physics

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A 2.9 kg lump of aluminum is heated to 94°C and then dropped into 8.0 kg of water at 5.4°C. Assuming that the lump-water system is
thermally isolated, what is the system's equilibrium temperature? Assume the specific heats of water and aluminum are 4186 and 900
J/kg-K, respectively.
Number
i
Units

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The density of ice and water are 917 kg/m³ and 1000 kg/m³. The latent heat for the transition between ice and water is 334 kJ/kg. Calculate the slope of the tangent of the coexistence curve of ice and water at T = 213 K. Select one: dP dT a. b. C. O d. dP dT dP dT dP dT = - -170 atm/K = — - - 181 atm/K -203 Pa/K -183 Pa/K
An ideal gas, at initial temperature T1 and initial volume 3.1 m3, is expanded adiabatically to a volume of 6.8 m³, then expanded isothermally to a volume of 17 m3, and then compressed adiabatically back to T1. What is its final volume? Number i Units
I2
A 2.6 kg lump of aluminum is heated to 96°C and then dropped into 11.0 kg of water at 5.4°C. Assuming that the lump-water system is thermally isolated, what is the system's equilibrium temperature? Assume the specific heats of water and aluminum are 4186 and 900 J/kg-K, respectively. Number i Units
A small electric immersion heater is used to heat 62 g of water for a cup of instant coffee. The heater is labeled “150 watts" (it converts electrical energy to thermal energy at this rate). Calculate the time required to bring all this water from 22°C to 100°C, ignoring any heat losses. (The specific heat of water is 4186 J/kg-K.) Number i Units
A small electric immersion heater is used to heat 50 g of water for a cup of instant coffee. The heater is labeled "180 watts" (it converts electrical energy to thermal energy at this rate). Calculate the time required to bring all this water from 25°C to 100°C, ignoring any heat losses. (The specific heat of water is 4186 J/kg-K.) Number i Units
Question 5 Specific Heat of Solid Substances Substance D Aluminum B silver; because it is a transition metal with the lowest specific heat value C Iron Copper Tin Given the specific heat information presented, which substance would make the BEST material to create a pan for cooking and why? D Specific Heat (J/kg°C) 899 443 385 213 Tin - because it has a low specific heat, which means it conducts heat the best. Aluminum - because it has a high specific heat, which means it conducts heat the best. Copper - because it has a mid-level specific heat, which means it is a good insulator. Iron - because it has a mid-level specific heat, which means it is a good conductor.
Ice at -12.1 °C and steam at 121 °C are brought together at atmospheric pressure in a perfectly insulated container. After thermal equilibrium is reached, the liquid phase at 44.1 °C is present. Ignoring the container and the equilibrium vapor pressure of the liquid at 44.1 °C, find the ratio of the mass of steam to the mass of ice. The specific heat capacity of steam is 2020 J/(kg C°). af Number i Initial state Units Steam - Ice Equilibrium Water
A small electric immersion heater is used to heat 83 g of water for a cup of instant coffee. The heater is labeled "69 watts" (it converts electrical energy to thermal energy at this rate). Calculate the time required to bring all this water from 19°C to 100°C, ignoring any heat losses. (The specific heat of water is 4186 J/kg-K.) Number i Units
Lead pellets, each of mass 1.90 g, are heated to 200°C. How many pellets must be added to 498 g of water that is initially at 20.0°C to make the equilibrium temperature 25.0°C? Neglect any energy transfer to or from the container. pellets Need Help? Read t
Inside the calorimeter, a 9O degrees Celsius sample was dropped in the water at room temperature. Conservation of energy states that * The summation of heat is equal to zero. Qcold = - Qhot The amount of energy that leaves the sample equals the amount of energy that enters the water and the calorimeter. O all of these
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