A 191-g particle is moving with a velocity v1 = i + j + 2k at a time ti = 1.2s. If the single force F in Newtons %3D F = (5.11 + 3.08t)i + (2.13 – 0.89t²)j + 3.02k acts on the particle, determine the magnitude (m/s) of its velocity at time t, = 4.23s.
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