A 150 gram block is attached to an ideal spring that oscillates on a frictionless, horizontal surface with a frequency of 2.50 Hz and an amplitude of 12.5 cm. (a) What is the spring (or force) constant of the spring? (b) If the gravitational potential energy is zero at the location of the block, then what is the total mechanical energy of the oscillator? (c) What is the magnitude of the maximum velocity of the block? (d) What is the magnitude of the maximum acceleration? (e) Include a diagram of the situation that indicated where the location of the maximum velocity and acceleration are located in the motion of the block.

A block attached to a spring is oscillating between point x (fully compressed) and point y (fully stretched). The spring is un-stretched at point 0. www y At point x, which of the following quantities is at its maximum value? X 0 O The block's kinetic energy O The blocks potential energy O kinetic energy and potential energy O neither kinetic energy nor potential energy

A toy bow is used to fire an arrow directly upwards. The spring constant of the bowstring is 17 N/m, and the arrow has mass 0.013 kg. If the bow is drawn 0.15 m before firing, calculate the speed of the arrow when it leaves the bow.

The diagram shows a horizontal spring attached to a block. The block’s equilibrium position is at C, and the block oscillates between the points A and E with no friction from the floor. As the block moves from C to E, which of the following statements is true? Usp is the spring potential energy of the spring and K is the kinetic energy of the block.

A 0.220-kg block resting on a frictionless, horizontal surface is attached to a spring having force constant 83.8 N/m as in the figure below. A horizontal force F causes the spring to stretch at a distance of 5.49 cm from its equilibrium position.   (a) Find the value of F. (Enter the magnitude of the force only.) N(b) What is the total energy stored in the system when the spring is stretched? J(c) Find the magnitude of the acceleration of the block immediately after the applied force is removed. m/s2(d) Find the speed of the block when it first reaches the equilibrium position. m/s(e) If the surface is not frictionless but the block still reaches the equilibrium position, how would your answer to part (d) change? The block would arrive at a greater speed. The block would arrive at a lower speed.     The block would arrive at the same speed. (f) What other information would you need to know to find the actual answer to part (d) in this case?

The length of a simple pendulum is 0.85 m and the mass of the particle (the “bob”) at the end of the cable is 0.32 kg. The pendulum is pulled away from its equilibrium position by an angle of 7.5° and released from rest. Assume that friction can be neglected and that the resulting oscillatory motion is simple harmonic motion.  Using the position of the bob at its lowest point as the reference level, determine the total mechanical energy of the pendulum as it swings back and forth.

OK, once again we have a pendulum, this time of length 1.18 m, which you release from rest at an angle of 46.8 degrees to the vertical. What will be the speed of the pendulum at the instant it reaches an angle of 37.4 degrees above the vertical?     3.51 m/s     1.59 m/s     2.70 m/s     2.18 m/s