A 140 g block attached to a spring with spring constant 2.2 N/m oscillates horizontally on a frictionless table. Its velocity is 15 cm/s when I = -5.3 cm ▼ What is the amplitude of oscillation? Express your answer with the appropriate units. ► View Available Hint(s) A Submit Part B HA Value What is the block's maximum acceleration? Units units ?

“Since you have posted a question with multiple sub parts, we will provide the solution only to the first three sub parts as per our Q&A guidelines. Please repost the remaining sub parts separately.”Mass of block, Spring constant, Velocity of mass, Part A:Since the energy of the oscillator is conserved, the total energy of the system is constant and is equal to the sum of the kinetic and potential energies of the oscillator:E=K+Uwhere,k is the spring constantA is the amplitude of an object in simple harmonic motionm is the mass of the objectv is the velocity of the object at position xSolving for A, we get:Plugging the given values we have,Part B:The acceleration of the block has a maximum magnitude:Part C:The acceleration of the block has a maximum magnitude at its extreme position. So the position of maximum acceleration isPart A:Part B:Part C: