A 1300 kg car drives at 27 m/s over a circular hill that has a radius of 370 m as shown in (Figure 1). Figure V 30° 1 of 1 At the point shown in (Figure 1), what is the normal force on the car? Express your answer with the appropriate units. n= Value Submit μA Provide Feedback Request Answer Units ?

The grid runs from -5 to 5 on both axes. Drawn on this grid are four vectors, labeled A⃗ A→ through D⃗ D→. This problem will ask you various questions about these vectors. All answers should be in decimal notation, unless otherwise specified. A. What is the xcomponent of A→? B.What is the y component of A⃗ ? C.What is the y component of B⃗ ? D.What is the x component of C⃗ ? E. In ordered pair notation, write down the components of vector B⃗  F. In ordered pair notation, write down the components of vector D G.What is true about B⃗  and D⃗ ? They have different components and are not the same vectors. They have the same components but are not the same vectors. They are the same vectors.

Disk - 0.20 m A coin C of mass 0.050 kg is placed on a horizontal disk at a distance of 0.20 m from the center, as shown above. The disk rotates at a constant rate in the clockwise direction as seen from above. The coin does not slip, and the time it takes for the coin to make a complete revolution is 1.2 s. a. The figure below shows the disk and coin as viewed from above. Draw and label vectors on the figure below to show the instantaneous acceleration and linear velocity vectors for the coin when it is at the position shown. b. Determine the speed of the coin. c. The rate of rotation of the disk is gradually increased. The coefficient of static friction between the coin and the disk is 0.50. Determine the speed of the coin when it just begins to slip. d. If the experiment in part (c) were repeated with a second, identical coin glued to the top of the first coin, how would this affect the answer to part (c) ? Explain your reasoning.

Part E Find x-component of F = (20.0 N, 36.9° counterclockwise from the positive y-axis). Express your answer with the appropriate units. View Available Hint(s) Fx = Submit Part F Fy= μà Submit Value Find y-component of F = (20.0 N, 36.9° counterclockwise from the positive y-axis). Express your answer with the appropriate units. View Available Hint(s) µÅ Units Value ? Units ?

Stacked blocks and pulley Mass Ma lies on top of mass Mb, as shown. Assume Mb > Ma. The two blocks are pulled from rest by a massless rope passing over a pulley. The pulley is accelerated at rate A. Block Mb slides on the table without friction, but there is a constant friction force f between Ma and Mb due to their relative motion. Find the tension in the rope.

1. The block in the figure to the right remains motionless against the wall because of an applied force and the force of static friction between the block and the wall. The coefficient of static friction is μs. Which equation correctly describes the magnitude of the frictional force between the wall and the block?a. Ff=(mgcosθ)μsb. Ff= (Fasinθ–mg) μsc. Ff= (Facosθ – mg) μsd. Ff= Facosθμse. Ff= (Facosθ + mg) μs

he FBD of the block should have looked like this.       1.    A contestant in a winter sporting event pushes a block of ice  of mass m across a frozen lake as shown in the figure. The coefficient of static friction between the block and ice is μs, and the coefficient of kinetic friction is μk. θ is the angle the force makes with the x-axis. In this part, we are going to set-up Newton's second Law equations for the cases(1) when the ice block just starts moving, and(2) when it is accelerating to the right with an acceleration a. All answers are symbolic. ALL ANSWERS ARE CASE-SENSITIVE.         Subpart 1: Newton's Second Law along the y-axis  (i) Write Newton's Second Law along the y-axis by adding all forces in the y-direction taking into account their signs (forces pointing upwards are positive and downward are negative) in terms of the normal force N, weight mg, F and θ. In both scenarios, there is no acceleration along the y-direction, therefore, ay=0.…

M Support Cable 37° M As shown in the diagram above, a rigid rod of mass M is hinged at its left end against a wall. A block of mass M hangs on the right edge of the rod. A support cable attached to the right end of the rod forms an angle of 37 degrees with horizontal. The tension in the string is 1,057 N. Calculate the mass M of the rod and the block. Express your answer in kilograms and round to the nearest tenth (1 decimal).

Pls help ASAP. Pls show all work and calculations.

Nilo