A 12.37 g sample of silver nitrate is reacted with 11.9 g of barium chloride according to the equation: 2AGNO3 (aq) + BaCl2 (aq) → 2AGCI(s) + Ba(NO3)2 (aq) Use the following data: MM AGNO3= 169.91 g/mol, MM Bacl2= 208.2 g/mol MM AgCl= 143.35 g/mol, MM Ba(NO3)2= 261.32 g/mol 1. How many grams of AgCl are formed? A. 16.39 g В. 10.44 в C. 14.94 g D. 9.51 g 2. How many grams of Ba(NO3)2 are formed? A. 16.39 g C. 14.94 g В. 10.44 g D. 9.51 g 3. What is the limiting reactant? C. AgCI D. Ba(NO3)2 A. AGNO3 В. Васi2

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A 12.37 g sample of silver nitrate is reacted with 11.9 g of barium chloride
according to the equation:
2AGNO3 (aq) + Bacl2 (aq) → 2AGCI(s) + Ba(NO3)2 (aq)
Use the following data: MM AGNO3= 169.91 g/mol, MM Bacl2= 208.2 g/mol
MM AgCl= 143.35 g/mol, MM Ba(NO3)2= 261.32 g/mol
1. How many grams of AgCl are formed?
С. 14.94 g
А. 16.39 g
В. 10.44 g
D. 9.51 g
2. How many grams of Ba(NO3)2 are formed?
C. 14.94 g
D. 9.51 g
3. What is the limiting reactant?
C. AgCI
D. Ba(NO3)2
А. 16.39g
В. 10.44
A. AGNO3
В. ВаCi2
Transcribed Image Text:A 12.37 g sample of silver nitrate is reacted with 11.9 g of barium chloride according to the equation: 2AGNO3 (aq) + Bacl2 (aq) → 2AGCI(s) + Ba(NO3)2 (aq) Use the following data: MM AGNO3= 169.91 g/mol, MM Bacl2= 208.2 g/mol MM AgCl= 143.35 g/mol, MM Ba(NO3)2= 261.32 g/mol 1. How many grams of AgCl are formed? С. 14.94 g А. 16.39 g В. 10.44 g D. 9.51 g 2. How many grams of Ba(NO3)2 are formed? C. 14.94 g D. 9.51 g 3. What is the limiting reactant? C. AgCI D. Ba(NO3)2 А. 16.39g В. 10.44 A. AGNO3 В. ВаCi2
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