A 12.0-V battery is attached to a 2.00-mF capacitor and a 100-Ω resistor. Once the capacitor is fully charged, what is the energy stored in it? What is the energy dissipated as heat by the resistor as the capacitor is charging?

If a voltage source of 24.0 V is connected from top to bottom, what is the charge accumulated on the 3.5 µF capacitor, in µC, when fully charged?

You have two parallel plate capacitors, C 1a = 10 nF and C 2a = 20 nF, each with the same area of 2 m^2 that is filled with a dielectric material that is 1 mm thick.   a) If the capacitors are connected in series vs parallel, which provides more total capacitance?   b) What is the difference in total energy if the capacitors are connected in series vs. parallel?   c) What dielectric material would you use in order to make the total capacitance of the capacitors connected in series equal to if they were connected in parallel?  Help...

Consider four capacitors connected to a 9.0-V battery in the configuration shown in the diagram. The capacitors have the followving capacitances: Cq is 7.4 µF, C2 is 6.4 µF, C3 is 12.4 µF and C4 is 4.1 µF. C1 C3 9.0V C2 C4 (a) Calculate the equivalent capacitance of the configuration shows in the diagram and the total energy stored by the equivalent capacitance. Be sure to explain your reasoning. (b) Find the potential difference across each capacitor and the charge stored on each capacitor. Be sure to explain your reasoning and show your work . Summarize your answers in a table like the one below in your hand-written answer: Capacitance: Potential Difference: Charge C;= AV;= Qı= Cz= AVz= Q²= C3= AV3= Q3= C4= AV== Q«=

A parallel combination of a 1.31 µF capacitor and a 2.73 pF capacitor is connected in series to a 4.53 µF capacitor. This three-capacitor combination is connected to a 19.5 V battery. Determine the charge on each capacitor. charge of 4.53 uF capacitor: 0.00003895 C charge of 1.31 µF capacitor: 0.0000096 charge of 2.73 uF capacitor: 0.0000242 C

Four uncharged capacitors with equal capacitances are combined in parallel. The combination is connected to a 7.23 V battery, which charges the capacitors. The charging process involves 0.000475 C of charge moving through the battery. Find the capacitance C of each capacitor.

Question 2: #46       With the switch open, the potential difference across the capacitor in Figure below is 10.0 V. After the switch is closed, how long will it take for the potential difference across the capacitor to decrease to 5.0 V?

To provide the pulse of energy needed for an intense bass, some car stereo systems add capacitors. One system uses a 2.0 F capacitor charged to 24 V, double the normal 12 V provided by the car’s battery. How much energy does the capacitor store at 12 V? At 24 V?

The capacitance of each of the four capacitors shown is 500 μF. The voltmeter reads 1 000V. The magnitude of the charge, in coulombs, on the equivalent capacitor is: Choices: 0.125.0.500.2.000.20.000.50.000.

In the figure below, capacitor 1 (C₁ 29.0 μF) initially has a potential difference of 59.0 V and capacitor 2 (C₂ = 6.00 μF) has none. The switches are then closed simultaneously. C₁ = = C₂ (a) Find the final charge on each capacitor after a long time has passed. Q1 C с (b) Calculate the percentage of the initial stored energy that was lost when the switches were closed. %