A parallel combination of a 1.31 µF capacitor and a 2.73 µF capacitor is connected in series to a 4.53 pF capacitor. This three-capacitor combination is connected to a 19.5 V battery. Determine the charge on each capacitor. charge of 4.53 µF capacitor: 0.00003895 charge of 1.31 pF capacitor: 0.0000096 charge of 2.73 uF capacitor: 0.0000242

Q2

Two capacitors, C1 = 5.92 µF and C2 = 3.30 µF, are connected in parallel, then the combination is connected to a 250 V battery. When the capacitors are charged, each one is removed from the circuit. Next, the two charged capacitors are connected to each other so that the positive plate of one capacitor is connected to the negative plate of the other capacitor. What is the resulting charge on each capacitor (in µC)? q′1= 421 µC q′2= 234 µC   (b) What If? What is the resulting charge on each capacitor (in µC) if they are instead charged as a series combination and then connected positive plate to positive plate and negative plate to negative plate? q′1= q′2=    solved the first two I need help with the bottom two it has to be in the format of the first two thank you

Find the following. (In the figure use C1 = 37.80 µF and C2 = 31.80 µF.)   (a) the equivalent capacitance of the capacitors in the figure above µF(b) the charge on each capacitor on the right 37.80 µF capacitor  µC on the left 37.80 µF capacitor  µC on the 31.80 µF capacitor  µC on the 6.00 µF capacitor  µC (c) the potential difference across each capacitor on the right 37.80 µF capacitor  V on the left 37.80 µF capacitor  V on the 31.80 µF capacitor  V on the 6.00 µF capacitor  V