A 100.0-mL sample of spring water was treated to convert any iron present to Fe. Titration with 25.00-mL of 0.002497 M K2C12O7 resulted in the reaction 6Fe+ + Cr20, 2- + 14H* → 6Fe* 1 2Cr** + 7H2O The excess K2Cr207 was back-titrated with 7.45 mL of 0.00953 M Fe2* solution. Calculate the concentration of iron in the sample in parts per million.

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Chapter18: Electrochemistry
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. A 100.0-mL sample of spring water was treated to convert any iron present to Fe*.
Titration with 25.00-mL of 0.002497 M K2Cr2O7 resulted in the reaction
6FE2+ + Cr0, 2- + 14H* → 6FE3* 1 2Cr** + 7H2O
The excess K2Cr207 was back-titrated with 7.45 mL of 0.00953 M Fe2* solution.
Calculate the concentration of iron in the sample in parts per million.
Transcribed Image Text:. A 100.0-mL sample of spring water was treated to convert any iron present to Fe*. Titration with 25.00-mL of 0.002497 M K2Cr2O7 resulted in the reaction 6FE2+ + Cr0, 2- + 14H* → 6FE3* 1 2Cr** + 7H2O The excess K2Cr207 was back-titrated with 7.45 mL of 0.00953 M Fe2* solution. Calculate the concentration of iron in the sample in parts per million.
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