A 10.0 mL solution of 0.660 M NH3 is titrated with a 0.220 M HCl solution. Calculate the pH after the following additions of the HCl solution: 0.00 mL, 10.0 mL, 30.0 mL, and 40.0 mL. Be sure your answer has the correct number of significant digits. Note: Reference the K of acids at 25 °C and K, of bases at 25 °C tables for additional information. Part 1 of 4 0.00 mL Added, pH = DP ☐ x10 ⑤ Part 2 of 4 Part 3 of 4 10.0 mL Added, pH = 20.0 mL Added U G

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Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.149QP: A solution of weak base is titrated to the equivalence point with a strong acid. Which one of the...
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A 10.0 mL solution of 0.660 M NH3 is titrated with a 0.220 M HCl solution. Calculate the pH after the following additions of the HCl solution: 0.00 mL,
10.0 mL, 30.0 mL, and 40.0 mL. Be sure your answer has the correct number of significant digits.
Note: Reference the K of acids at 25 °C and K₂ of bases at 25 °C tables for additional information.
a
Part 1 of 4
0.00 mL Added, pH:
□×10
x10
Part 2 of 4
10.0 mL Added, pH:
☐ x10
Part 3 of 4
30.0 mL Added, pH =
☑
[
☐
Transcribed Image Text:A 10.0 mL solution of 0.660 M NH3 is titrated with a 0.220 M HCl solution. Calculate the pH after the following additions of the HCl solution: 0.00 mL, 10.0 mL, 30.0 mL, and 40.0 mL. Be sure your answer has the correct number of significant digits. Note: Reference the K of acids at 25 °C and K₂ of bases at 25 °C tables for additional information. a Part 1 of 4 0.00 mL Added, pH: □×10 x10 Part 2 of 4 10.0 mL Added, pH: ☐ x10 Part 3 of 4 30.0 mL Added, pH = ☑ [ ☐
Part 4 of 4
40.0 mL Added, pH =
☐ x10
☑
Transcribed Image Text:Part 4 of 4 40.0 mL Added, pH = ☐ x10 ☑
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