Question
A 1.60 mol sample of an ideal monatomic gas, originally at a pressure of 1.60 atm. undergoes a three-step process: (1) it is expanded adiabatically from T1 = 586 KK to T2 = 386 KK ; (2) it is compressed at constant pressure until its temperature reaches T3; (3) it then returns to its original pressure and temperature by a constant-volume process.
Determine T3
Calculate the change in internal energy for each process.
Calculate the work done by the gas for each process.
Calculate the heat added to the gas for each process.
Calculate the change in internal energy, the work done by the gas, and the heat added to the gas for the complete cycle.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution
Trending nowThis is a popular solution!
Step by stepSolved in 6 steps with 6 images
Knowledge Booster
Similar questions
- 1.013 x 10° Pa) and We consider a 5.15-L sample of monatomic ideal gas at atmospheric pressure (1 atm 302 K. This initial state would be called point A, if we were to draw the process on a pV diagram (you should!). The gas is then heated at constant volume to 3.00 atm (point B). It then undergoes an isothermal expansion (point C) and is then compressed isobarically to its original state (point A). a. What is the number of moles of the sample? mol b. What are the temperatures at point B? K c. What are the temperatures at point C? K d. What is the volume at point C? L e. During the isothermal expansiom (B to C), calculate the following quantities The change in internal energy AE = %3D The work done by the gas is W = kJ The heat added to the gas is Q = kJ %3Darrow_forwardplease help mearrow_forwardA 2.00 mol sample of an ideal diatomic gas at a pressure of 1.10 atm and temperature of 420 K undergoes a process in which its pressure increases linearly with temperature. The final temperature and pressure are 720 K and 1.70 atm . Fid the change in internal energy, work done by the gas, and heat added.arrow_forward
- The picture shows a pV diagram for an ideal gas in which its pressure tripled from a to b when 804 J of heat was put into the gas. Work done on or by the gas between a and b= 0 W Delta U=804 J a) What is the temperature of the gas at point bb in terms of its temperature at a, Ta?arrow_forwardA monatomic ideal gas initially fills a V0 = 0.35 m3 container at P0 = 75 kPa. The gas undergoes an isobaric expansion to V1 = 1.5 m3. Next it undergoes an isovolumetric cooling to its initial temperature T0. Finally it undergoes an isothermal compression to its initial pressure and volume. 1. Calculate the heat absorbed Q2, in kilojoules, during the isovolumetric cooling (second process). 2. Calculate the change in internal energy by the gas, ΔU2, in kilojoules, during the isovolumetric cooling (second process). 3. Calculate the work done by the gas, W3, in kilojoules, during the isothermal compression (third process). 4. Calculate the change in internal energy, ΔU3, in kilojoules, during the isothermal compression (third process). 5. Calculate the heat absorbed Q3, in kilojoules, during the isothermal compressions (third process).arrow_forwardQ.44 A gas is enclosed in a cylinder of volume Vo fitted with piston of cross-sectional area A and mass m. Atmospheric pressure is Po. Adiabatic exponent of gas is y. The piston is slightly depressed and released. (A) Time period of oscillation of piston if the process is isothermal is 2π (B) Time period of oscillation of piston if the process is adiabatic is 2π (C) Time period of oscillation of piston if the process is isothermal is 2π (D) Time period of oscillation of piston if the process is adiabatic is 2π mVo VA²Po ymVo A²Po mVo AP mVo √ YA²Po Poarrow_forward
- Suppose a monatomic ideal gas is changed from state A to state D by one of the processes shown on the PV diagram. PA Isotherms P₂2 atm P₁ atm A kJ E IN T B C 1 1 L I 4.00L 8.00L 16.0L V where P₁ = 1.10 and P₂ = 2.20. mat is the total work done on the gas if it follows the constant-temperature path AC followed by the constant-pressure path CD?arrow_forwardFind the total change in the internal energy of a gas that is subjected to the following two-step process. In the first step the gas is made to go through isochoric heating until it gains 5863 J and its pressure is 3.72 x 10° Pa. In the second step it is subjected to isobaric adiabatic compression until its volume decreases by 7.50 x 103 m³. What is the total change in .internal.energy.,of this gas? Enter a number. Finition of isochoric and isobaric processes. What is the work done during each process? Jarrow_forwardYou would like to raise the temperature of an ideal gas from 295 K to 960 K in an adiabatic process. a)What compression ratio will do the job for a monatomic gas? b)What compression ratio will do the job for a diatomic gas?arrow_forward
arrow_back_ios
arrow_forward_ios