A 1.50-in.-diameter solid shaft is subjected to an axial force of P = 1700 lb, a horizontal shear force of V = 180 lb, and a concentrated torque of T = 2200 lb-in., acting in the directions shown. Assume L = 7.5 in. Section properties for the shaft are A = 1.7671 in.2, J = 0.497 in.4, Iy = Iz = 0.2485 in.4, and Q = 0.2812 in.3. Determine the normal and shear stresses at point K, and show these stresses on a stress element

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter3: Torsion
Section: Chapter Questions
Problem 3.11.7P: A thin-walled steel tube having an elliptical cross section with constant thickness t (see figure)...
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A 1.50-in.-diameter solid shaft is subjected to an axial force of P = 1700 lb, a horizontal shear force of V = 180 lb, and a concentrated torque of T = 2200 lb-in., acting in the directions shown. Assume L = 7.5 in.  Section properties for the shaft are A = 1.7671 in.2J = 0.497 in.4Iy = Iz = 0.2485 in.4, and Q = 0.2812 in.3.  Determine the normal and shear stresses at point K, and show these stresses on a stress element.

A 1.50-in.-diameter solid shaft is subjected to an axial force of P = 1700 lb, a horizontal shear force of V= 180 lb, and a concentrated
torque of T = 2200 Ib-in., acting in the directions shown. Assume L= 7.5 in. Section properties for the shaft are A = 1.7671 in.?, J=
0.497 in.4, ly = 1z= 0.2485 in.“, and Q = 0.2812 in.3. Determine the normal and shear stresses at point K, and show these stresses on a
stress element.
H
T
Answer:
Ox =
i
psi
Tyy
i
psi
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Transcribed Image Text:A 1.50-in.-diameter solid shaft is subjected to an axial force of P = 1700 lb, a horizontal shear force of V= 180 lb, and a concentrated torque of T = 2200 Ib-in., acting in the directions shown. Assume L= 7.5 in. Section properties for the shaft are A = 1.7671 in.?, J= 0.497 in.4, ly = 1z= 0.2485 in.“, and Q = 0.2812 in.3. Determine the normal and shear stresses at point K, and show these stresses on a stress element. H T Answer: Ox = i psi Tyy i psi eTextbook and Media Save for Later Attempts: 0 of 1 used Submit Answer
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