College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A -1.11 nC point charge is located inside a cavity of a hollow sphere of
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- A= 19 cm^2arrow_forwardanswer is not 1.62*10^-6 and is not 4011.86 and is not 20131.55 and i will dislike of you put any of these answers and u need to give a numerical answer (not an equation with variables) otherwise i will dislikearrow_forwardPart a) A +6 nC charge is located 3.6 meters to the right of a +5 nC charge. Determine the magnitude of the electric field at the midpoint of the two charges. Express your answer as a positive number in N/C. Part b) A 10 nC charge generates an electric field within an isolated chamber. At a point a distance d meters away from the charge, the electric field is measured to be 4 N/C. Determine d in meters. Use k=9 x109 for the electric constant.arrow_forward
- A positive charge q is fixed at point (−4, 3) and a negative charge -q is fixed at point (-4,0). Determine the net electric force Fnet acting on a negative test charge -Q at the origin (0, 0) in terms of the given quantities and physical constants, including the permittivity of free space Eo. Express the force using ij unit vector notation. Enter precise fractions rather than entering their approximate numerical values. F net = = 4- 3- 2- 1- -1- -2- -3- y 2 4arrow_forwardA certain spherical charge cloud has a volume charge density p(r) = Po e-r²/a² p2 [C/m³] where r is the radius in spherical coordinates, and a is a positive real constant. What must the constant po be if the total charge in the cloud is Q? 0≤r<∞0arrow_forwardSuppose three charges: q = 4.00 nC, q, =-4.00 nC, q3 =2.40 nC are enclosed by five surfaces as shown below.Give the electric flux through each surface. Input all numerical values in three significant figures. Do not forget to include the sign if the value is negative.arrow_forward
- needs complete typed solution with 100 % accuracy.arrow_forwardTwo flat conductors are placed with their in- ner faces separated by 16 mm. If the surface charge density on inner face A is 105 pC/m and on inner face B is -105 pC/m², calculate the electric po- tential difference AV VA VB- Use €0 = 8.85419 x 10¬12 c² /Nm². Answer in units of V. %3Darrow_forwardNCS-1 A non-conducting sphere of radius R=0.300m has a total charge q-100μC that is evenly distributed throughout its volume. a) Find the charge within a radius of r=0.100m. Hint: first find the volume charge density p. b) Find the electric field strength at r=0.100m. c) Find the charge within a radius of r-0.200m. d) Find the electric field strength at r-0.200m. e) Find the charge within a radius of 1-0.300m. f) Find the electric field strength at r-0.300m. g) How does E change with increasing radius? Rarrow_forward
- Express the following quantities in SI units: 23.4 grams = 2.34 x 10^-2 124 millimeters = 1 hour and 24 min = 0.12 centimeters =arrow_forwardNeed this with explanationarrow_forwardFollowing the previous question, the x-component of the net electric field at x = -1.00 m, Enet.x , is N/C. Use normal format and 3 significant figures.arrow_forward
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