A 1.0x10-3 V/m electric field creates a 3.0x1017 elec/s current in a 1.3-mm-diameter aluminum wire. Part A What is the drift speed? Express your answer with the appropriate units. HÅ Vvd = 3.77 106 m S Submit Previous Answers Request Answer ? × Incorrect; Try Again; 27 attempts remaining Part B What is the mean time between collisions for electrons in this wire? Express your answer with the appropriate units. ΜΑ ? T = Value Units

How many electrons strike the screen each second? 2.94x1014 electrons The electron beam inside a television picture tube is 0.300 mm in diameter and carries a current of 47.0 µA. This electron beam impinges on the inside of the picture tube screen. Submit Previous Answers v Correct Part B What is the current density in the electron beam? Eνα ΑΣφ A/m² Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Review your calculations and make sure you round to 3 significant figures in the last step. Part C The electrons move with a velocity of 3.90 x107 m/s. What electric field strength is needed to accelerate electrons from rest to this velocity in a distance of 5.80 mm ? ? N/C Submit Request Answer Part D Each electron transfers its kinetic energy to the picture tube screen upon impact. What is the power delivered to the screen by the electron beam? να ΛΣφ. ? 0.2734 Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining

I need help with both parts, part A and Part B

A 50-A current is running through a cylindrical wire that has a cross-sectional area of 4.0 mm2. The drift velocity of the conduction electrons in the wire is 0.85 mm/s. What is the numebr density of the conduction electrons in the wire?   a. 9.2 x 1028 electrons/m3   b. 1.4 x 1029 electrons/m3   c. 3.2 x 1030 electrons/m3   d. 4.6 x 1028 electrons/m3   e. 5.7 x 1029 electrons/m3