An aluminum wire 1.291 mm in diameter (16-gauge) carries a current of 3 amps. Overall Hint a. What is the number density of charge carriers (electrons) in the wire? Hint for (a) 1 The number density of electrons in the wire is m³ (Use "E" notation to enter your answer in scientific notation. For example, to enter 3.14 × 10¹², enter "3.14E12".) b. What is the magnitude of the drift velocity of the electrons? Hint for (b) The drift velocity of the electrons is va m/s. c. What would be the drift velocity if the same gauge copper were used instead of aluminum? Hint for (c) For the same gauge copper wire, the drift velocity would be vd = m/s. There is a disconnect between how small drift velocities are and how quickly electrical signals travel through wires (nearly at the speed of light). For the moment, treat the two as completely unrelated to each other.

In a wire with a 2.17 mm2 cross-sectional area, 7.19 × 1020 electrons flow past any point during 3.09 s. What is the current I in the wire? I = A Determine the current density J. J = A/m?

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Two pieces of copper wire have the same length, but wire A has square cross section of side s, whereas wire B has circular cross section of diameter s. Which of the following is TRUE? A. The resistivity of both wires is the same B. The resistance of both wires is the same C. The resistance of wire A is greater than B D. The resistance of wire B is greater than A

F2 An aluminum wire 1.628 mm in diameter (14-gauge) carries a current of 5 amps. Overall Hint a. What is the number density of charge carriers (electrons) in the wire? # 3 3 Hint for (a) 1 The number density of electrons in the wire is m³ (Use "E" notation to enter your answer in scientific notation. For example, to enter 3.14 × 10¹2, enter "3.14E12".) b. What is the magnitude of the drift velocity of the electrons? Hint for (b) The drift velocity of the electrons is vd = c. What would be the drift velocity if the same gauge copper were used instead of aluminum? Hint for (c) For the same gauge copper wire, the drift velocity would be va r Question Help: Message instructor Submit Question There is a disconnect between how small drift velocities are and how quickly electrical signals travel through wires (nearly at the speed of light). For the moment, treat the two as completely unrelated to each other. 80 F3 54 $ 4 F4 C do 5 % F5 ㅏ < 6 6 MacBook Air F6 = & 7 8 AA m/s. F7 * 8 m/s. DII F8…

E28. According to a safety code, the maximum allowable current for a 14 gauge copper wire (diameter, 1.628 mm) is 15 A, and it is 5 A for an 18 gauge wire (diameter 1.024 mm). What would be the potential difference between the ends of a 10m length of each type of wire for maximum current? ∆V14 = 1.23 V ; ∆V18 = 1.03 V Please show steps and formulas for my own understanding.

A steel wire, of length L and diameter D, has a resistance of 100 . What current would flow through a silver wire of the same diameter and the same length if a 13.0 V potential difference were applied across its length? Express your answer in amperes. I = ΠΫΠΙ ΑΣΦ ! You have already submitted this an No credit lost. Try again. Submit ? Previous Answers Request Answer A Enter a new answer.

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