A 1.00-L insulated bottle is full of tea at 91.5A?°C. You pour out a mug of tea and immediately screw the stopper back on the bottle. Find the change in temperature of the tea remaining in the bottle that results from the admission of air at room temperature. (Let the room temperature be 20.0A?°C and assume that you poured out 180 cm3 of tea. Take the molar mass of air as 28.9 g/mol and A?air = 1.20 10-3 g/cm3. Here we define a "monatomic ideal gas" to have molar specific heats CV = (3/2)(R) and CP =(5/2)(R), and a "diatomic ideal gas" to have CV = (5/2)(R) and CP = (7/2)(R)). A?°C

A silver block, initially at 56.9 ∘C∘C, is submerged into 100.0 gg of water at 24.1 ∘C∘C, in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 27.4 ∘C∘C.     What is the mass of the silver block? Express your answer to two significant figures and include the appropriate units.

On a chilly 10°C day, you quickly take a deep breath—all your lungs can hold, 4.0 L. The air warms to your body temperature of 37°C. If the air starts at a pressure of 1.0 atm, and you hold the volume of your lungs constant (a good approximation) and the number of molecules in your lungs stays constant aswell (also a good approximation), what is the increase in pressure inside your lungs?

A student decides to conduct an experiment by using two different flasks and two different gas samples. In flask 1, there exists Neon (Ne) gas, whereas the second flask is filled with nitrogen (N2) gas. If both flasks are kept at 270 K, answer the following questions. (Note: Molar mass of N2 = 28.014 g mol1,molar mass of Neon = 20.1797 g mol, R= 8.31 J. mol1.K1, k=1.38 x 1023 J.K-1, Avogadro's number = 6.02 x 1023 mol1.) a) Find the average kinetic energy of one Neon molecule. b) Calculate the average kinetic energy (translational+rotational) of one nitrogen molecule by including rotational motion in your calculations. c) Find the root-mean-square speed of one neon molecule. V ms1 Check

2.40 moles of an ideal gas is initially at 40.0 oC and 1.35 atm. a) What is its volume under these conditions?b) If it is then compressed to one third of its initial volume and its pressure increases to 2.0 atm, what, in Centigrade degrees, will be its temperature?

A hollow aluminum cylinder 19.5 om deep has an internal capacity of 2.000 L at 21.0°C. It is completely filled with turpentine at 21.0°C. The turpentine and the aluminum cylinder are the slowly warmed together to 79.0°C. (The average linear expansion coefficient for aluminum is 24 x 10-c, and the average volume expansion coefficient for turpentine is 9.0 103) (a) How much turpentine overflows? cm³ (b) What is the volume of turpentine remaining in the cylinder at 79 0°C? (Give your answer to at least four significant figures) (c) If the combination with this amount of turpentine is then cooled back to 21.0°C, how far below the cylinder's rim does the turpentine's surface recede? om

Homework 2: Problem 7:   When builders were constructing a sidewalk they forgot to include an expansion joint between two of the segments, L = 1.7 m at To = 20° C. Assume the opposite ends of each segment are fixed and the linear expansion coefficient is α = 11.8 × 10-6 °C-1. Part (a)  As the day heats to Tb the segments press against each other and begin to raise the junction a distance h forming a triangle. What is the height (in meters) at Tb=110° F? h = ______ m Part (b)  What should the gap have been, in units of meters, to prevent them from touching? g = ______m

At a temperature of 39.5 °C a 0.4-mm gap exists between the ends of the rods shown. At a later time when the temperature has reached 129.1°C, determine the change in length of the steel rod if L = 306.32 mm and M = 226 mm. Round off the final answer to four decimal places.