A 0.75-kg cart is pulled along a horizontal track by a rope. The rope m of 30 degrees to the horizontal. Your friend says that the normal component of the force the track exer is 7.5 N because mg = (0.75kg) (10) = 7.5N. Do you agree with your friend? Use a force diagram and Newton's 2nd
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- Your cat "Ms." (mass 7.00 kg) is trying to make it to the top of a frictionless ramp 2.00 m long and inclined upward at 30.0 ° above the horizontal. Since the poor cat can't get any traction on the ramp, you push her up the entire length of the ramp by exerting a constant 100 N force parallel to the Part A If Ms. takes a running start so that she is moving at 2.40 m/s at the bottom of the ramp, what is her speed when she reaches the top of the incline? Use the work-energy theorem. ramp. m/sThe slope of the 4.1 kN force F is specified as shown in the figure. Express F as a vector in terms of the unit vectors i and j. Assume a = 9, b = 3. Answer: F = (i it i j) KN15. Gotta stay boosted. A 1.50 [kg] box moves along a frictionless horizontal surface with an initial speed of 5.00 [m/s] going to the right. A constant 3.00 [N] force is then applied to the box at an angle 0 = 35.0° with respect to the displacement vector. What is its final speed after moving 2.00 [m]? A. 4.91 [m/s] B. 5.62 [m/s] C. 5.74 (m/s] D. 6.00 [m/s]
- Problems: 210, 211, 216, 218, 231, 233, 238, 242, 257, 264 I. In the figure below, the x-component of the force P is 140 lb to the left. Determine P and its y- component. P 7 ww YA 1520-N crate is to be held in place on a ramp that rises at 30.0° above the horizontal (see figure). The massless rope attached to the crate makes a 22.0° angle above the surface of the ramp. The coefficients of friction between the crate and the surface of the ramp are uk = 0.450 and ls = 0.650 The pulley has no appreciable mass or friction. What is the MAXIMUM weight w that can be used to hold this crate stationary on the ramp? w = ? 22.0° Crate Ramp 30.0°a bridge across a small stream is made by supporting a 10m long log with a mass of 75kg with ropes tied at the ends of the log to the tree on the banks. the rope on the right makes a 25 degree angle with the ground. the rope on the left makes a 20 degree angle with the ground. a 25kg child us standing 7.5 m from the left bank. write the net force equation for the y direction. write the net force equation for the x direction. write the torque equation (use the left end of the log as the axis of rotation).
- A desperate hiker has to think fast to help his friend who has fallen below him. Quickly, he ties a rope to a rock of mA = 405 kg and makes his way over the ledge (see the figure below). If the coefficient of static friction between the rock and the ground is H=0.348, and the mass of the hiker is ma= 70.1 kg, what is the maximum mass of the friend, mc, that the rock can hold so the hikers can then make their way up over the ledge? Assume the rope is parallel to the ground and the point where the rope passes over the ledge is frictionless. (ANS: 70.8 kg)A 400 N body starts up a 30 degree incline (f=D0.2) with a velocity of 3m/s. a. How long must a 500 -N horizontal force act on the body to increase its velocity to 8m/sec? (s) b. How far will the body travel while the force is acting? (m) NOTES ON ANSWERING FOR THIS PROBLEM: 1. ANSWER IN POSITIVE VALUES ONLY 2. ANSWER IN 1 DECIMAL PLACE ONLY (i.e. IF YOUR FINAL ANSWER IS 6.82, INPUT 6.8 IF YOUR FINAL ANSWER IS 19.55 ANSWER 19.6) 400 N 500 N 0.2N 300 N.You are a bully. You pin a 48 kg dweeb to a wall so that his feet aren't touching the ground. Your arm is extended so that it makes an angle 28 degrees with the horizontal. The dweeb's back is so sweaty with fear that there is no friction between his back and the wall. What is the magnitude of the force , in N, you must apply to keep the dweeb in equilibrium? (Use g = 10 m/s2) This scenario is represented schematically below. Unfortunately for you, years later the dweeb is your boss and he makes your life miserable. (Please answer to the fourth decimal place - i.e 12.3445)
- In the very Dutch sport of Fierljeppen, athletes run up to a long pole and then use it to vault across a canal as shown in (Figure 1). At the very top of his arc, a 70 kg vaulter is moving at 2.9 m/s and is 5.5 m from the bottom end of the pole. What is the magnitude of the vertical force that the pole exerts on the vaulter? Express your answer with the appropriate units.A 9.50 kg block is at rest on a horizontal floor, and then you pull it with a cord that exerts a tension force of 12.0 N on the block at an angle of 24.0o above the horizontal. The coefficient of kinetic friction between the block and the floor is 0.055. What is the speed of the block 0.85 s after it starts moving? Nothing I do is working! I only have three more tries to get it right and what should be working is not.A 400-N body starts up the incline of 30o with the horizontal (fk = 0.2) with a velocity of 3m/s. a. How long must a 500-N horizontal force act on the body to increase its velocity to 8m/s? b. How far will the body travel while the force is acting?