College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A block is attached to a spring with a sping constant of 7.6 N/m and it undergoes simple harmonic motion. The amplitude of the blocks motion is 6.30 cm. When the block is halfway between its equilibrium position and the end point of it's motion, its speed is measured to be 28.9 cm/s. Calculate : (a) the mass of the block, (b) the period of the motion, and (c) the maximum acceleration of the block.arrow_forwardTwo massless springs with spring constants 610 N/m and 116 N/m are hung from a hor- izontal support. A block of mass 6 kg is suspended from the pair of springs, as shown. When the block is in equilibrium, each spring is stretched an additional Ar. Then the block oscillates with an amplitude of 49 m and it passes through its equilibrium point with a speed of 539 m/s. 610 N/m -oooo² 6 kg -0000² 116 N/m What is the angular velocity of this system? The acceleration due to gravity is 9.8 m/s. 1. w = 15 2. w = 2 3. w = 11 rad/s 4. w = 13 5. w = 21 6. w = 16 7. w = 8 X 8. w = 4 9. w = 6 10. = 18arrow_forwardA block of unknown mass is attached to a spring with a spring constantof 5.50 N/m and undergoes simple harmonic motion with an amplitude of 12.5 cm.When the block is halfway between its equilibrium position and the end point, itsspeed is measured to be 26.0 cm/s.(a) Calculate the mass of the block.(b) Calculate the period of the motion.(c) Calculate the maximum acceleration of the block.arrow_forward
- An apple weighs 1.04 NN. When you hang it from the end of a long spring of force constant 1.54 N/mN/m and negligible mass, it bounces up and down in SHM. If you stop the bouncing and let the apple swing from side to side through a small angle, the frequency of this simple pendulum is half the bounce frequency. (Because the angle is small, the back and forth swings do not cause any appreciable change in the length of the spring.) What is the unstretched length of the spring (i.e., without the apple attached)? Express your answer with the appropriate units.arrow_forwardA spring with spring constant 15.0 N/m hangs from the ceiling. A ball is suspended from the spring and allowed to come to rest. It is then pulled down 6.00 cm and released. If the ball makes 30 oscillations in 20.0 s, what are its (a) mass and (b) maximum speed?arrow_forwardA spring Is suspended vertically from a celling. When a 2.80-kg mass is attached to the bottom of the spring, Its equilibrlum length Increases by 4.00 cm. If the mass Is further pulled down by 5.00 cm from its new equilibrlum length and released, what is the frequency of the simple harmonic motion?arrow_forward
- The amplitude of a 2.40-kg mass oscillating on a horizontal frictionless surface is 13.5 cm. If thespring to which the mass is attached has a spring constant of 8.24 x 10^3N/m, then what is the maximum speed of the mass?arrow_forwardA mass on a spring, moving with simple harmonic motion, vibrates with a frequency of 4.0 Hz and an amplitude of 8.0 cm. If x = 8.0 cm when t = 0, find its speed when t = 3 s.arrow_forward(a) A device consists of an object with a weight of 35.0 N hanging vertically from a spring with a spring constant of 250 N/m. There is negligible damping of the oscillating system. Applied to the system is a harmonic driving force of 13.0 Hz, which causes the object to oscillate with an amplitude of 3.00 cm. What is the maximum value of the driving force (in N)? (Enter the magnitude.) N (b) What If? The device is altered so that there is a damping coefficient of b = 5.00 N s/m. The hanging weight and spring constant remain the same. The same driving force as found in part (a) is applied with the same frequency. What is the new amplitude (in cm) of oscillation? cm (c) What If? Repeat the same calculation as part (b), only now with a damping coefficient of b = 100 N s/m. (Enter the answer in cm.) cmarrow_forward
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