9:12 STARTING AMOUNT ADD FACTOR x( ) A liquid in the lab has a density of 1.17 g/cm³. What is the volume in liters of 3.02 kg of the liquid? 3.53 1 3.02 2.58 3.53 x 10³ 10 2.58 x 10³ Question 25 of 40 0.001 1.17 cm³ mL L kg g/cm³ g X .. LTE ANSWER Submit RESET 5
9:12 STARTING AMOUNT ADD FACTOR x( ) A liquid in the lab has a density of 1.17 g/cm³. What is the volume in liters of 3.02 kg of the liquid? 3.53 1 3.02 2.58 3.53 x 10³ 10 2.58 x 10³ Question 25 of 40 0.001 1.17 cm³ mL L kg g/cm³ g X .. LTE ANSWER Submit RESET 5
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Density and Volume Calculation Exercise**
**Question 25 of 40**
---
**Problem Statement:**
A liquid in the lab has a density of 1.17 g/cm³. What is the volume in liters of 3.02 kg of the liquid?
---
**Interactive Prompt:**
- There are interactive sections where you can input the values to solve the problem:
- **Starting Amount**: Enter the given mass of the liquid (3.02 kg).
- **Multiplication Section**: This area is used to input the conversion factors and calculators suitable for solving the problem.
---
**Available Values for Calculation**:
- **Blue Buttons**:
- 3.53
- 1
- 3.02
- 2.58
- 3.53 x 10³
- 10³
- 2.58 x 10³
- 0.001
- 1.17
- **Red Buttons**:
- cm³
- mL
- L
- kg
- g/cm³
- g
**Functional Buttons**:
- **x ()**: Adds a multiplication factor.
- **= [ ]**: Computes the answer.
- **Reset**: Clears all input fields and starts fresh.
**Instructions**:
1. Identify the known values:
- Density: 1.17 g/cm³
- Mass: 3.02 kg
2. Convert the mass from kg to g:
- Use the conversion factor: 1 kg = 1000 g
- 3.02 kg = 3.02 x 1000 = 3020 g
3. Use the density formula to find the volume:
- Density (ρ) = mass (m) / volume (V)
- Rearrange to find Volume: V = m / ρ
- Substitute the known values: V = 3020 g / 1.17 g/cm³ ≈ 2580.34 cm³
4. Convert cm³ to liters (since 1 mL = 1 cm³ and 1000 mL = 1 L):
- Volume in liters: 2580.34 cm³ / 1000 ≈ 2.580 L
The calculated volume of the liquid is approximately **2.580](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc25e6886-23a3-4870-9519-3bb0f78f33bc%2F2dc32ce5-f15a-4c02-92ee-4c0b4f30b85b%2Fn4i1p2d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Density and Volume Calculation Exercise**
**Question 25 of 40**
---
**Problem Statement:**
A liquid in the lab has a density of 1.17 g/cm³. What is the volume in liters of 3.02 kg of the liquid?
---
**Interactive Prompt:**
- There are interactive sections where you can input the values to solve the problem:
- **Starting Amount**: Enter the given mass of the liquid (3.02 kg).
- **Multiplication Section**: This area is used to input the conversion factors and calculators suitable for solving the problem.
---
**Available Values for Calculation**:
- **Blue Buttons**:
- 3.53
- 1
- 3.02
- 2.58
- 3.53 x 10³
- 10³
- 2.58 x 10³
- 0.001
- 1.17
- **Red Buttons**:
- cm³
- mL
- L
- kg
- g/cm³
- g
**Functional Buttons**:
- **x ()**: Adds a multiplication factor.
- **= [ ]**: Computes the answer.
- **Reset**: Clears all input fields and starts fresh.
**Instructions**:
1. Identify the known values:
- Density: 1.17 g/cm³
- Mass: 3.02 kg
2. Convert the mass from kg to g:
- Use the conversion factor: 1 kg = 1000 g
- 3.02 kg = 3.02 x 1000 = 3020 g
3. Use the density formula to find the volume:
- Density (ρ) = mass (m) / volume (V)
- Rearrange to find Volume: V = m / ρ
- Substitute the known values: V = 3020 g / 1.17 g/cm³ ≈ 2580.34 cm³
4. Convert cm³ to liters (since 1 mL = 1 cm³ and 1000 mL = 1 L):
- Volume in liters: 2580.34 cm³ / 1000 ≈ 2.580 L
The calculated volume of the liquid is approximately **2.580
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