Please determine the total mg/mL that you were able to recover from the column= experimental yield. Please show your data and calculation Online students the volume is 1.5 mL and the OD 550 is 0.35. elow is a standard curve I generated that you can use. OD 550 vs. mg/mL OD 550 4 3. 2 1 O 0.2 0.4 0.6 0.8 1.0 mg/mL

Please determine the total mg/mL that you were able to recover from the column= experimental yield. Please show your data and calculation Online students the volume is 1.5 mL and the OD 550 is 0.35. elow is a standard curve I generated that you can use. OD 550 vs. mg/mL OD 550 4 3. 2 1 O 0.2 0.4 0.6 0.8 1.0 mg/mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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2.00 mL OF 5.80 x10-"M AGNO g 245.0 mL of 3.35 X10 M NazS and + Na, Scaas 2 NANO3 tazy 248.19 1549 2709 2 Ag NO3 78.19 Nans Agzs 2 NANO3 inirial Change Final
Remaining Time! 02:29:4. Consider the balanced chemical equations shown below. When a 6.00 g sample of a mixture of iron (Fe) and aluminum (Al) is treated with excess HCl(aq), 0.177 moles of H2 are obtained. What is the mass percentage of Fe in the original mixture? Choose the closest answer. Fe(s) + 2 HCI(aq) FeCl2(aq) - + H2(g) 2 Al(s) +6 HC((aq) 2 AICI3(aq) + 3 H2(g) 96 % 69 % 47 % 33 % 17 % Rack Question Menu - O O
Q) A student misreads the directions and adds 4.0 g of benzoic acid instead of 0.4 g. What do you expect to happen? Would the experiment still be valid? Explain your reasoning. Pure Lauric Acid Lauric Acid + 0.4 g Benzoic Acid Lauric Acid + 0.5 g Benzoic Acid Mass of Lauric Acid 3.03g 3.00g 3.00g Mass of Benzoic Acid 0 g 0.40g 0.50g Freezing Point 43’C 39’C 38’C Freezing Point Depression * 4’C 5’C Molality of Benzoic Acid in Lauric Acid* 1.026 mol/kg 1.282 mol/kg Moles of Benzoic Acid * 0.003 moles 0.004 moles Experimental Molar Mass of Benzoic Acid * 133.3g/mol 125 g/mol Average Molar Mass * 129.15g/mol Percent Error * 5.75%
Consider the following chemical reaction. C,H1,(g) + 0,(g) Co, (g) + H,O(g) Select the coefficients that will properly balance the equation. O 1,11,4, 8 O 2, 13, 8, 10 13 O 1,4,5 O 1,7, 4, 5 O 4, 26, 16, 20
The following volumes of 0.000300 M SCN are diluted to 15.00 mL. Determine the concentration of SCN in each sample after dilution. These values will be used during the experiment. To enter exponential values, use the format 1.0e-5. Sample 0.000300 M SCN (mL) [SCN'] (M) 1 1.50 3.50 7.00 4 10.00 3.
Remaining Time: 1 hour, 01 minute, 47 seconds. * Question Completion Status: QUESTION 2 The number of water molecules in 2.3 mg of water is O 6.02 x 1023 O 77.0 x 1023 O 7.7 x 1023 O 7.7 x 1019 none of the above QUESTION 3 A ctudent makes a colution bu discolvina 254a ofNDOH int0 450 gof water Wh. Click Save and Submit to save and submit. Click Save All Answers to save all answer ere to search DELL
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Can you answer it as if you where putting it in those boxes. Set the equation up
Determine the number of molecules of Cr,0; that form when 1.34 x 103 g of oxygen completely reacts according to the following equation: 4 Cr(s) + 3 O2(g) → 2 Cr2O3(s) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) |2.52 х 1025 152.00 4.24 x 103 |3.78 х 1025 3 1.68 х 1025 4 6.022 x 1023 1.34 x 10° 52.00 32.00 1 g O2 g Cr203 mol Cr2O3 molecules Cr203 mol Cr g Cr mol O2
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Conc. of NaOH: TRIAL 1 TRIAL 2 TRIAL 3 Mass of flask 81.061 69.692 96.039 Mass of flask and vinegar 83.010 71.578 97.940 Mass of vinegar 1.949 1.886 1.901 Volume of vinegar 2.00 2.00 2.00 Initial buret reading Final buret reading 17.0 17.5 16.0
Volume (mL) Trial 1 Trial 2 Trial 3 Final volume (mL) 24.35 47.60 20.60 Initial volume (mL) 1.25 25.15 42.85 Volume Added 23.10 22.45 22.35 Average Volume Added 22.63 mL Concentration of NaOH 0.9971 M % Acetic Acid in Vinegar Assuming all the acid to be acetic, calculate the number of grams of acid per 100 mL of vinegar solution. Assuming that the density of vinegar is 1.000, what is the percentage of acetic acid by weight in vinegar? Average your results in the usual manner. % of Acetic Acid = (mL of NaOH added)(concentration of NaOh)/mL of vinegar sample