9.2 cm   29.8 cm   13.7 cm   22.9 cm

How do I find the following with the data provided:   Refractive index of acrylic, Speed of light through acrylic,

Three sheets of plastic have unknown indices of refraction. Sheet 1 is placed on top of sheet 2, and a laser beam is directed onto the sheets from above so that it strikes the interface at an angle of 26.6deg with the normal. The refracted beam in sheet 2 makes an angle of 31.4deg with the normal. The experiment is repeated with sheet 3 on top of sheet 2 and, with the same angle of incidence, the refracted beam makes an angle of 36.8deg with the normal. If the experiment is repeated again with sheet 1 on top of sheet 3, what is the expected angle of refraction in sheet 3? Assume the same angle of incidence.

Please refer again to Figure 2.   The incident ray is coming in from water (n=1.33) rather than air. And this time, theta = 52.2 degrees, y = 31.9 cm and h = 1.13 cm. What is x now?       33.6 cm     42.0 cm     12.6 cm     50.4 cm

A light ray in incidnet on slab #1 at 30°. It gpes through slab #2 and then reaches slab #3. What is the incident angle on slab #2.  (n1=1.80  n2=1.50  n3=1.30) 38.23° 0.60° 23.35° 55.77° none

The figure below shows the path of a light beam through several slabs with different indices of refraction. (n4 = 1.01) 10% = n = 1.60 n = 1.40 n = 1.20 14 (a) If 01 35.0°, what is the angle 02 of the emerging beam? 63.12 X Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error.º

Use the exact values you enter to make later calculations.A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.96) at an angle of ? = 32.4° with respect to the normal (see figure below). A light ray incident on a glass block of thickness 2.00 cm is shown. The ray travels down and to the right and is incident to the top of the block at an angle ? to the normal of the surface. The ray inside the block moves down and to the right but at a steeper slope than the incident ray. It is incident on the bottom surface of the block and exits moving down and to the right, in the same direction as the incident ray. A dashed line extends from the original path of the ray down in the block and is shown to be a distance d from the ray that exits the glass block. (a) Find the angle of refraction at the top surface and the angle of incidence at the bottom surface. °(b) Find the refracted angle at the bottom surface. °(c) Find the lateral distance d by which the light beam is shifted. cm(d)…