
Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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Transcribed Image Text:2. Text Ishibashi Soil Mechanics Fundamentals and Applications- Ishibashi 420 PAGES.pdf - Adobe Acrobat Reader DC (64-bit)
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Given the following conditions:
Specimen diameter = 76.0 mm
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Initial specimen height = 12.7 mm
Weight of dry specimen = 50.6 gf
Gs = 2.70
(a) Compute and plot e-log o relation.
(b)
Determine preconsolidation stress by Casagrande's method.
Compute the compression index Cc.
(c)
(d)
Is this soil normally consolidated or overconsolidated if the
specimen's current effective overburden stress is 150 kP
9.11 A soil profile is shown in the following figure. A new footing will be
placed on the ground and the average vertical stress increment at the
midpoint of the clay layer due to the new footing will be Ao, = 25.5 kPa.
Estimate the final primary consolidation settlement of the clay layer.
Assume that the clay is normally consolidated.
New footing
2.8 m
Ydry 18.0 kN/m³
W.T.
4.2 m
Ywet 18.6 kN/m³
3.0 m
Ywet = 18.2 kN/m³, e,= 0.82
LL = 44, PL = 20
Sand
Sand
Clay
9.60
9.79
10.02
Sand
EP
C
100%
28°C Partly sunny
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- 8.4 A rectangular foundation is shown in Figure P8.2, given B= 2 m, L=4m q=240 kN/m², H=6m, and D; =2 m. (a) Assuming E = 3800KN/m², calculate the average elastic settlement. Use Eq. (8.24). (b) If the clay is normally consolidated, calculate the consolidation settlement. Use Eq. (8.35) and yat = 17.5 kN/m², C¸ = 0.12, and e, = 1.1.arrow_forwardQuestion 3 a) In a geotechnical laboratory an oedometer test on a saturated clay soil was conducted. The results in the laboratory report stated that the Ce= 0.2, C, -0.04 and OCR = 4.5. The existing vertical effective stress in the field was 130 kPa. A shallow foundation was designed to construct above the soil condition. This will increase the vertical stress at the center of the clay by 50 kPa. The thickness of the clay layer is 2 m and its water content is 28%. Solve the primary consolidation settlement and determine the difference in the settlement if OCR value were 1.5 instead 4.5.arrow_forwardsubject: Geotechnical Engineeringbook: principle of foundation engineering - Braja M Dasarrow_forward
- Estimate the ultimate consolidation settlement under the centerline of a 25 x 25 meter mat foundation. The mat is 1.5 meter thick reinforced concrete (ϒconcrete = 23.6 kN / m3), and the average stress on the surface of the slab is 125 kPa. The soil profile is shown in the figure below. Lab testing on samples of the clay showed that the clay is normally consolidated and that Cc = 0.40, Cr = 0.03, and eo = 1.13. Neglect any settlements due to the sand layer. Divide the clay layer into four thinner layers of thickness 2.0, 2.0, 3.0, and 3.0 meters.arrow_forward75% consolidation in a laboratory test? 11.21 Refer to Figure 11.48. A square foundation, 2.5 × 2.5 m in size, supports a col- umn load of 478 kN. The soil characteristics are given in the figure. Field moni- toring indicated that the foundation settlement was 46 mm at the end of 2 years a. Estimate the average stress increase in the clay layer due to the applied load. b. Estimate the primary consolidation settlement. c. What is the degree of consolidation after 2 years? d. Estimate the coefficient of consolidation for the pressure range. e. Estimate the settlement in 3 years. 478 kN 2.5 m x 2.5 m 1.5 m Y = 16 kN/m GWT 1.75 m Yu = 18.8 kN/m³ w = 19% G, = 2.71 LL = 37 3.5 m o = 65 kN/m? C,= 1/SC. %3D O Sand A Clay Figure 11.48arrow_forwardA circular foundation 2m in diameter is shown in the figure below. A normallyconsolidated clay layer 5m thick is located below the foundation. Determine the consolidation settlement of the clay. 1- method 2:1 2- consolidation settlement Cc methodarrow_forward
- 4. Calculate the total settlement of two clay layers? The two clay samples at Location A and Location B were collected and analyzed. Use information at Location A to estimate the settlement at the stiffy silty clay. Use information at Location B to estimate the settlement at the very stiff clay. Compression index C, at point A is 0.25, C, at point B is 0.2. Swelling index C, at point A is 0.08, C, at point B is 0.06. Initial void ratio eo at point A is 0.66, eo at point B is 0.45. Maximium vertical stress cat point A is 101 kPa, at point B is 510 kPa. The 8.5 m thick proposed fill generated a increase of vertical stress = 20.3x8.5 = 172.55 kPa. 8.5 m 2.0 m 3 m 7.0m 4 m 4 mⒸ 4 m5 18.0m 5 mo 5 m Proposed Fill y=20.3 kN/m² y-18.3 kN/m² 7-19.0 kN/m² y-19.5 kN/m² 4.0 Stiff Silty Clay (CL) 10.0 Very Stiff Clay (CL) Glacial Tillarrow_forwardKINDLY OBTAIN THE RIGHT ANSWER AND EXPLAIN Refer to Figure. Given that B =1 m, L = 3 m, and Q = 110 kN, the soil characteristics given in the figure are Cs = 1/5 Cc, Ꝺ’c= 40 kN/m2. Field monitoring indicated that the foundation settlement was 19 mm during the first 12 months. Estimate the average stress increase in the clay layer due to the applied load. Estimate the primary consolidation settlement. What is the degree of consolidation after 12 months? Estimate the coefficient of consolidation for the pressure range. Estimate the settlement in 24 months.arrow_forwardA circular foundation 2m in diameter is shown in the figure below. A normallyconsolidated clay layer 5m thick is located below the foundation. Determine the consolidation settlement of the clay. 1- method 2:1 2- consolidation settlement Cc methodarrow_forward
- Answer in three decimal places pleasearrow_forwardA 5-ft fill is to be placed over the following soil profile shown below. Determine if the clay is normally consolidated or over-consolidated. The pre-consolidation pressure (past maximum consolidation stress) of the clay is 1000 lb/ft3. 5 ft 2 ft 4 ft Proposed Fill, y = 120 lb/ft³ Sand Clay Rock 2 ft A Ydry = 100 lb/ft³ Ground water table Ysat 110 lb/ft³ = o'= Pc = 1000 lb/ft²arrow_forward11.17 A plate load test was conducted in sand on a 300 mm diameter plate. If the plate settlement was 5 mm at a pressure of 100 kPa, the settlement (in mm) of a 5 m x 8 m rectangular footing at the same pressure will bearrow_forward
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