Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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- 7) A square magnetic core has a mean path length of 55 cm and a cross- sectional area of 150 cm². A 200-turn coil of wire carrying a current of 0.316 A is wrapped around one leg of the core. What is the magnetomotive force created by the system?arrow_forwardProblem 4 The magnetic circuit shown in the figure has two windings and two air gaps. The core can be be of infinite 8: |- Core, u o0 Arca A2 assumed to permeability. dimensions are indicated in the The core Area A N turns figure. inductances of windings 1 and 2 Find the self- 81 Na turas and the mutual inductance between the windings.arrow_forwardPls quick. I need the final answerarrow_forward
- A ten-turn solenoid has a ferromagnetic core with a relative permeability of 10,000. The length of the solenoid is l=10 cm and its cross section area is A=1 cm2. The amount of current driving the solenoid is 0.1 A. Determine the magnetic flux intensity H in the core. Provide your answer in A/m. Round off to your answer to one decimal.arrow_forwardA core with three legs is shown in the figure below. The depth of the core is 5cm, and there are 100 turns on the leftmost leg. The relative permeability of the core can be assumed to be 2000 and constant. What flux exists in each of the three legs of the core? What is the magnetic field in each of the legs? Assume a 5percent increase in the effective area of the air gap due to fringing effects. 9 cm 9 cm 25 cm 15 cm -25 cm 9 cm 2 A 100 turns 0.05 cm 25 cm 9 cm Core depth = 5 cmarrow_forwardA coil has a field intensity at 300 At. Its length is doubled from 20 to 40 cm for the same magnetomotive force. What is the new magnetic field intensity?arrow_forward
- A ferromagnetic core with a relative permeability of 1500 is shown in the following figure. The depth of the core is 5 cm. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 300 turns in the coil wrapped around the center leg of the core, and if the current in the coil is 1.25 A, find the magnetic flux and the field density in all three legs of the core, as well as the magnetic flux and flux density in the two air gaps.arrow_forwardA magnetic core with an air gap is shown below. For a relative permeability is 3500, and the space free permeability is 4x10-7 H/m. Find the reluctance of the left leg and the top side of the core. 5 cm gap 0.15 cm Select one: a. 40 cm N core depth = 10 cm O b. Rleft = 13.642 C. None 5 cm 1 5 cm 20 cm 15 cm Rleft = 1364.2 A.t./Wb, Rtop = 2045.5 A.t/Wb KA.t./Wb, Rtop = 20.455 KA.t/Wb d. Rleft = 20.455 KA.t./Wb, Rtop = 13.642 KA.t/Wb Oe. Rleft = 1.36 KA.t./Wb, Rtop = 2.05 KA.t/Wbarrow_forwardPlease help me with this question.arrow_forward
- Consider the circuit in the figure (b). The curved segments are arcs of circles of angle 350 and radii a = 30 cm and b = 15 cm. The straight segments are along radii. Find the magnetic field B at point P (the center of curvature), assuming a current of 18 A clockwise in the circuit. (Positive out of page and negative into page) a R2 Ө b R1 P A H C J D (b) (a)arrow_forwardQ4// A ring of a mean diameter 30 cm and cross sectional area of 15 cm2 is made up of semi – circular sections of cast iron and cast steel. If each joint has an air gap of 0.25 mm. Find amper turns required to produce a flux of 7 x 10 weber in the magnetic circuit. The relative permeability of steel and iron are 852 and 165 respectively. - OA- Amper turns required= 1105 OB- Amper turns required= 1995 OC- Amper turns required= 2250 OD- Amper turns required= 3150 OE- None of above ارسال الاجابةarrow_forwardA thin conducting wire is bent into the shape shown in the figure. The circular portion of the wire has radius R. The wire is in the plane of the screen and carries a current I. R (a) What is the direction of the magnetic field at the center of the loop? O to the left O to the right O upward O downward O into the screen O out of the screen (b) Find an expression for the magnitude of the magnetic field at the center of the loop. (Use the following as necessary: R, I, and Ho. Do not substitute numerical values; use variables only.) B =arrow_forward
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