9-46. The press consists of two rigid heads that are held together by the two A36 steel 12-mm-diameter rods. A 6061-T6-solid-aluminum cylinder is placed in the press and the screw is adjusted so that it just presses up against the cylinder. Determine the angle through which the screw can be turned before the rods or the specimen begin to yield. The single-threaded screw on the bolt has a lead of 0.25 mm. Note: The lead represents the distance the screw advances akıng its axis for one complete turn of the screw. -300 mm - so mm -250

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8-21. The elastic portion of the stress-strain diagram for an aluminum alloy is shown in the figure. The specimen from which it was obtained has an original diameter of 12.7 mm and a gage length of 50.8 mm. When the applied load on the specimen is 50 kN, the diameter is 12.67494 mm. Determine Poisson's ratio for the material. 8-22. The elastic portion of the stress-strain diagram for an aluminum alloy is shown in the figure. The specimen from which it was obtained has an original diameter of 12.7 mm and a gage length of 50.8 mm. If a load of P = 60 kN is applied to the specimen, determine its new diameter and length. Take v = 0.35. σ (MPa) 490 0.007 Probs. 8-21/22 € (mm/mm)

When the two forces are placed on the beam, the diameter of the A-36 steel rod BC decreases from 40 mm to 39.96 mm. (Figure 1) Figure -1 m -1 m P -1 m- B 0.75 m 1 m Part A Determine the magnitude of each force P. Express your answer to three significant figures and include the appropriate units. P = μA Value KN Submit Previous Answers Request Answer Provide Feedback ? X Incorrect; Try Again; 2 attempts remaining

The rod has a circular cross section. If it is made of an elastic perfectly plastic material, determine the shape factor.

An axial load is applied to the rectangular cross section bar which is welded at the 57 degree angle shown. If the weld material has a failure normal stress of 160 mPa and a failure shear stress of 90 mPa, determine the required thickness if a factor of safety of 2.3 is required. Also determine the required diameter of the bolts(to the nearest mm) if the plate is face bolted to the supports. The bolt material has a failure shear stress of 175 mPa.

The acrylic plastic rod is 200 mm long and 15 mm in diameter. If an axial load of 300 N is applied to it, determine the change in its length and the change in its diameter. Ep = 2.70 GPa, np = 0.4.

The long bolt passes through the 70.4-mm-thick plate. If the force in the bolt shank is 9.5 KN, then the average shear stress (MPa) along the cylindrical area of the plate defined by the section lines a-a is: O a. 0.00 O b. 21.00 O c. 2.39 O d. 4.77 O e. 1.19 18 mm b b 8 mm Time left 0:45:52 a 7 mm YouTube The wood beam has an allowable shear stress of 15 MPa, the maximum shear force V (kN) that can be lind to the cross section is:

Determine the resulting maximum value of the normal stress. Specify the orientation of the plane on which these maximum values occur.   **The answer is tensile stress is 0 ksi at 90 degrees.  **The answer is compressive stress is 7 ksi at 0 degrees.  Can you explain how that is? This was my thought process: I know that tensile would be zero because the force P is actually going inwards and not outwards. I know that means that there would be a compressive force. I am confused on the angles, how is a tensile force going 90 degress if there technically is no force in the tensile direction. And how is there a compressive force at 90 degrees if there is a stress? thank you!