8.4 A rectangular foundation is shown in Figure P8.2, given B = 2 m, L= 4m q = 240 kN/m², H = 6 m, and D; = 2 m. (a) Assuming E = 3800KN/m², calculate the average elastic settlement. Use Eq. (8.24). (b) If the clay is normally consolidated, calculate the consolidation settlement. Use Eq. (8.35) and y,t = 17.5 kN/m’, C, = 0.12, and e, = 1.1. G.W.T. 2 m = 240 kN/m² 2 m x 4 m Clay H-6m ea = 1.10 Rock Figure P8.2

Principles of Foundation Engineering (MindTap Course List)
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Author:Braja M. Das
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Chapter7: Settlement Of Shallow Foundations
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Problem 7.6P
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8.4 A rectangular foundation is shown in Figure P8.2, given B=2m, L=4m
q = 240 kN/m², H = 6m, and D; = 2 m.
(a) Assuming E = 3800KN/m², calculate the average elastic settlement. Use
Eq. (8.24).
(b) If the clay is normally consolidated, calculate the consolidation settlement.
Use Eq. (8.35) and y,t = 17.5 kN/m’, C, = 0.12, and e, = 1.1.
%3D
G.W.T.
D,=2 m
= 240 kN/m²
Clay
e. = .IO
H= 6 m
1.
Rock
Figure P8.2
S,(average) = µ,M0
qB
(v = 0.5)
E
(8.24)
(8.35)
Transcribed Image Text:8.4 A rectangular foundation is shown in Figure P8.2, given B=2m, L=4m q = 240 kN/m², H = 6m, and D; = 2 m. (a) Assuming E = 3800KN/m², calculate the average elastic settlement. Use Eq. (8.24). (b) If the clay is normally consolidated, calculate the consolidation settlement. Use Eq. (8.35) and y,t = 17.5 kN/m’, C, = 0.12, and e, = 1.1. %3D G.W.T. D,=2 m = 240 kN/m² Clay e. = .IO H= 6 m 1. Rock Figure P8.2 S,(average) = µ,M0 qB (v = 0.5) E (8.24) (8.35)
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