Help please 8.9.MY NOTES ASK YOUR TEACHER10.PRACTICE ANOTHERWhat average mechanical power (in W) must a 76.5 kg mountain climber generate to climb to the summit of a hill of height 285 min 41.0 min? Note: Due to inefficiencies in converting chemical energy to mechanical energy, the amount calculated here is only afraction of the power that must be produced by the climber's body.HINTMY NOTESDETAILSHINTWSERCP11 5.7.P.051.DETAILSMY NOTESA student evaluates a weight loss program by calculating the number of times he would need to climb a 15.0 m high flight ofsteps in order to lose one pound (0.45 kg) of fat. Metabolizing 1.00 kg of fat can release 3.77 x 107 J of chemical energy and thebody can convert about 21.4% of this into mechanical energy (the rest goes into internal energy.)SERCP11 5.A.P.074.ASK YOUR TEACHER PRACTICE ANOTHER(a) How much mechanical energy (in J) can the body produce from 0.450 kg of fat?(b) How many trips up the flight of steps are required for the 52.0 kg student to lose 0.450 kg of fat? Ignore the relatively smallamount of energy required to return down the stairs.tripsDETAILSSERCP11 5.A.P.081.ASK YOUR TEACHER PRACTICE ANOTHERA truck travels uphill with constant velocity on a highway with a 6.5° slope. A 45-kg package sits on the floor of the back of thetruck and does not slide, due to a static frictional force. During an interval in which the truck travels 325 m, find the following.(a) What is the net work done on the package?(b) What is the work done on the package by the force of gravity?(c) What is the work done on the package by the normal force?(d) What is the work done on the package by the friction force? 1.MY NOTES2.ASK YOUR TEACHER PRACTICE ANOTHERA cable exerts a constant upward tension of magnitude 1.94 x 10 N on a 1.60 x 103 kg elevator as it rises through a verticaldistance of 1.90 m.HINT(a) Find the work done by the tension force on the elevator (in )).MY NOTES4.(b) Find the work done by the force of gravity on the elevator (in J).DETAILS SERCP11 5.1.P.003.HINTA tension force of 155 N inclined at 35.0° above the horizontal is used to pull a 31.0 kg shipping crate a distance of 4.10 m on arough surface. If the crate moves at a constant speed, find (a) the work done by the tension force and (b) the coefficient ofkinetic friction between the crate and surface.MY NOTESDETAILS SERCP11 5.1.P.007.ASK YOUR TEACHER PRACTICE ANOTHER(a) the work done by the tension force (in J)(b) the coefficient of kinetic friction between the crate and surfaceMY NOTESDETAILSSERCP11 5.2.P.011.ASK YOUR TEACHERA 66.6 kg runner has a speed of 4.50 m/s at one instant during a long-distance event.|HINT(a) What is the runner's kinetic energy at this instant (in J)?(b) How much net work (in J) is required to triple his speed?DETAILSPRACTICE ANOTHERSERCP115.5.P.026.ASK YOUR TEACHERPRACTICE ANOTHERTruck suspensions often have "helper springs that engage at high loads. One such arrangement is a leaf spring with a helper coilspring mounted on the axle, as shown in the figure below. When the main leaf spring is compressed by distance yo, the helperspring engages and then helps to support any additional load. Suppose the leaf spring constant is 4.90 x 105 N/m, the helperspring constant is 3.40 x 105 N/m, and y=0.500 m.Main leafspringTruck body-"HelperspringAxleQ(a) What is the compression of the leaf spring for a load of 4.70 x 105 N?m(b) How much work is done in compressing the springs?5.MY NOTES6.7.HINTA 25.0 cm long spring is hung vertically from a ceiling and stretches to 29.5 cm when an 8.00 kg mass is hung from its free end.MY NOTESDETAILS SERCP11 5.6.P.034.(a) Find the spring constant (in N/m).N/mASK YOUR TEACHER(b) Find the length of the spring (in cm) if the 8.00 kg weight is replaced with a 215 N weight.MY NOTEScmDETAILS SERCP11 5.6.P.038.ASK YOUR TEACHERTwo blocks are connected by a light string that passes over a frictionless pulley as in the figure below. The system is releasedfrom rest while m₂ is on the floor and m, is a distance h above the floor.=201(a) Assuming m, m₂, find an expression for the speed of m, just as it reaches the floor. (Use any variable or symbolstated above along with the following as necessary: g.)(b) Taking m₁ = 6.0 kg, m₂ = 4.3 kg, and h = 3.3 m, evaluate your answer to part (a).m/sPRACTICE ANOTHER(c) Find the speed of each block when m, has fallen a distance of 1.1 m.m/sDETAILS189T₁ASK YOUR TEACHERPRACTICE ANOTHERT₂171The system shown in the figure below is used to lift an object of mass m = 72.0 kg. A constant downward force of magnitude Fisapplied to the loose end of the rope such that the hanging object moves upward at constant speed. Neglecting the masses of therope and pulleys, find the following.SERCP11 5.6.P.043.(a) Find the required value of F.NPRACTICE ANOTHER(b) Find the tensions T₁ T2 and T3. (T3 indicates the tension in the rope which attaches the pulley to the ceiling.)T₁NT₂NT3 =N(c) Find the work done by the applied force in raising the object a distance of 2.70 m.kJ

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Description: Help please 8.9.MY NOTES ASK YOUR TEACHER10.PRACTICE ANOTHERWhat average mechanical power (in W) must a 76.5 kg mountain climber generate to climb to the summit of a hill of height 285 min 41.0 min? Note: Due to inefficiencies in converting chemical

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Help please 8.9.MY NOTES ASK YOUR TEACHER10.PRACTICE ANOTHERWhat average mechanical power (in W) must a 76.5 kg mountain climber generate to climb to the summit of a hill of height 285 min 41.0 min? Note: Due to inefficiencies in converting chemical energy to mechanical energy, the amount calculated here is only afraction of the power that must be produced by the climber's body.HINTMY NOTESDETAILSHINTWSERCP11 5.7.P.051.DETAILSMY NOTESA student evaluates a weight loss program by calculating the number of times he would need to climb a 15.0 m high flight ofsteps in order to lose one pound (0.45 kg) of fat. Metabolizing 1.00 kg of fat can release 3.77 x 107 J of chemical energy and thebody can convert about 21.4% of this into mechanical energy (the rest goes into internal energy.)SERCP11 5.A.P.074.ASK YOUR TEACHER PRACTICE ANOTHER(a) How much mechanical energy (in J) can the body produce from 0.450 kg of fat?(b) How many trips up the flight of steps are required for the 52.0 kg student to lose 0.450 kg of fat? Ignore the relatively smallamount of energy required to return down the stairs.tripsDETAILSSERCP11 5.A.P.081.ASK YOUR TEACHER PRACTICE ANOTHERA truck travels uphill with constant velocity on a highway with a 6.5° slope. A 45-kg package sits on the floor of the back of thetruck and does not slide, due to a static frictional force. During an interval in which the truck travels 325 m, find the following.(a) What is the net work done on the package?(b) What is the work done on the package by the force of gravity?(c) What is the work done on the package by the normal force?(d) What is the work done on the package by the friction force? 1.MY NOTES2.ASK YOUR TEACHER PRACTICE ANOTHERA cable exerts a constant upward tension of magnitude 1.94 x 10 N on a 1.60 x 103 kg elevator as it rises through a verticaldistance of 1.90 m.HINT(a) Find the work done by the tension force on the elevator (in )).MY NOTES4.(b) Find the work done by the force of gravity on the elevator (in J).DETAILS SERCP11 5.1.P.003.HINTA tension force of 155 N inclined at 35.0° above the horizontal is used to pull a 31.0 kg shipping crate a distance of 4.10 m on arough surface. If the crate moves at a constant speed, find (a) the work done by the tension force and (b) the coefficient ofkinetic friction between the crate and surface.MY NOTESDETAILS SERCP11 5.1.P.007.ASK YOUR TEACHER PRACTICE ANOTHER(a) the work done by the tension force (in J)(b) the coefficient of kinetic friction between the crate and surfaceMY NOTESDETAILSSERCP11 5.2.P.011.ASK YOUR TEACHERA 66.6 kg runner has a speed of 4.50 m/s at one instant during a long-distance event.|HINT(a) What is the runner's kinetic energy at this instant (in J)?(b) How much net work (in J) is required to triple his speed?DETAILSPRACTICE ANOTHERSERCP115.5.P.026.ASK YOUR TEACHERPRACTICE ANOTHERTruck suspensions often have &#34;helper springs that engage at high loads. One such arrangement is a leaf spring with a helper coilspring mounted on the axle, as shown in the figure below. When the main leaf spring is compressed by distance yo, the helperspring engages and then helps to support any additional load. Suppose the leaf spring constant is 4.90 x 105 N/m, the helperspring constant is 3.40 x 105 N/m, and y=0.500 m.Main leafspringTruck body-&#34;HelperspringAxleQ(a) What is the compression of the leaf spring for a load of 4.70 x 105 N?m(b) How much work is done in compressing the springs?5.MY NOTES6.7.HINTA 25.0 cm long spring is hung vertically from a ceiling and stretches to 29.5 cm when an 8.00 kg mass is hung from its free end.MY NOTESDETAILS SERCP11 5.6.P.034.(a) Find the spring constant (in N/m).N/mASK YOUR TEACHER(b) Find the length of the spring (in cm) if the 8.00 kg weight is replaced with a 215 N weight.MY NOTEScmDETAILS SERCP11 5.6.P.038.ASK YOUR TEACHERTwo blocks are connected by a light string that passes over a frictionless pulley as in the figure below. The system is releasedfrom rest while m₂ is on the floor and m, is a distance h above the floor.=201(a) Assuming m, > m₂, find an expression for the speed of m, just as it reaches the floor. (Use any variable or symbolstated above along with the following as necessary: g.)(b) Taking m₁ = 6.0 kg, m₂ = 4.3 kg, and h = 3.3 m, evaluate your answer to part (a).m/sPRACTICE ANOTHER(c) Find the speed of each block when m, has fallen a distance of 1.1 m.m/sDETAILS189T₁ASK YOUR TEACHERPRACTICE ANOTHERT₂171The system shown in the figure below is used to lift an object of mass m = 72.0 kg. A constant downward force of magnitude Fisapplied to the loose end of the rope such that the hanging object moves upward at constant speed. Neglecting the masses of therope and pulleys, find the following.SERCP11 5.6.P.043.(a) Find the required value of F.NPRACTICE ANOTHER(b) Find the tensions T₁ T2 and T3. (T3 indicates the tension in the rope which attaches the pulley to the ceiling.)T₁NT₂NT3 =N(c) Find the work done by the applied force in raising the object a distance of 2.70 m.kJ

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